To do this, we need molar mass, as well as Avogadro's Number.
To start, 1.60 x 10-12 grams C10H16O. Molar mass = 152.23 g/mol
Divide 1.60 x 10-12 grams by 152.23 g/mol to get a number in moles.
You should get 1.05 x 10-14 moles
From here, we use Avogadro's Numner, 6.022 x 10^23 molecules/mole.
Multiply our moles, 1.05 x 10-14 by 6.022 x 10^23
Answer:
6.33 x 10^9 molecules.
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Final amount =initial anount *(1/2)^(t/half life)
final amount =2.000 mg *(1/2)^(10.5/5.20) = 0.493 mg remain after 10.5 years