Answer:
Silver, 0.239 J/(g °C)
Explanation:
- The heat change is related to specific heat as given by the formula;
Heat change = mass of substance × specific heat × change in temperature
- Therefore; considering same amount of substance or equal masses and have the same initial temperature.
- The change in temperature will be inversely proportional to the specific heat.
- Therefore; the higher the specific heat lower the temperature change.
- Hence, the change in temperature will be highest for the substance with the lowest specific heat.
Therefore; the one that will increase in temperature the most is Silver
Answer:
Its atomic mass increases by 1
An isotope of that element is fotmed with mass differences by 1
Explanation:
Answer:
This question appears incomplete
Explanation:
However, it should be noted that addition of soluble salts generally lowers the freezing point of water hence after the addition, water will no longer freeze at 0°C but lower.
Soluble salts tend to form more ions in water, it is these ions that are responsible for interfering with the hydrogen bonds hence lowering the freezing. Thus, (since each bag are of the same weight) <u>the bag that contains the salt that ionizes more in water will lower the freezing point by the greatest amount</u>.
NOTE: Different weight of the salts could lead to more ions been formed in the water by some salts as against the other.
There are 0.566 moles of carbonate in sodium carbonate.
<h3>CALCULATE MOLES:</h3>
- The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.
- no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3
- Molar mass of Na2CO3 = 23(2) + 12 + 16(3)
- = 46 + 12 + 48 = 106g/mol
- mass of CO3 = 12 + 48 = 60g
- no. of moles of CO3 = 60/106
- no. of moles of CO3 = 0.566mol
- Therefore, there are 0.566 moles of carbonate in sodium carbonate.
Learn more about number of moles at: brainly.com/question/1542846
Let us assume that there is a 100g sample of Opal. The masses of each element will be:
29.2g Si
33.3g O
37.5g H2O
Now we divide each constituent's mass by its Mr to get the moles present
Si: (29.2 / 28) = 1.04
O: (33.3 / 16) = 2.08
H2O: (37.5 / 18) = 2.08
Now we divide by the smallest number and obtain:
Si: 1
O: 2
H2O: 2
Thus, the empirical formula of Opal is:
SiO2 . 2H2O
