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spayn [35]
3 years ago
12

Sodium bicarbonate is sometimes used to neutralize acid spills. If 2.0 L of 1.0 M H2SO4 is spilled, what mass of sodium bicarbon

ate (NaHCO3) is required to neutralize all the H2SO4?
Chemistry
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

168.0 g

Explanation:

First thing, write a balanced chemical equation:

H_{2}SO_{4}+ 2NaHCO_{3}  ----> Na_{2}SO_{4} + 2H_{2}O+2CO_{2}

n(H2SO4) = concentration * volume

                = 1.0 M * 2.0 L

                = 2.0 mol

According to the balanced equation, 1 mol of acid requires 2 mol of sodium bicarbonate. This means that 2 mol of acid requires 2 mol of sodium bicarbonate. What mass of sodium bicarbonate is this?

mass (NaHCO3) = number of moles * molar mass

                           = 2.0 mol * 84.0065 g/mol

                           = 168.0 g

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Phoenix [80]

Physical and chemical changes are reversible and nonreversible changes. The release of carbon dioxide gas indicates a chemical change.

<h3>What is a chemical change?</h3>

A chemical change is a change in which a new substance is produced when the reactants react in the reaction mixture. The chemical produced cannot be reversed back to the reactants and hence, it is nonreversible.

The release of carbon dioxide is a chemical change as limestone and hydrochloric acid react with each other chemically and as a result, a new substance was formed.

Therefore, the production of carbon dioxide indicates a chemical change.

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5 0
1 year ago
Pls help me this is my last question
asambeis [7]

Answer: how much mass is in a certain amount of space

Explanation: density is g/mL; therefore it’s the mass (g) in a certain amount of space (mL)

7 0
2 years ago
Read 2 more answers
How many grams of Lead(II) nitrate are present in 150.0 mL of an Lead(II) nitrate solution that is 0.07268 M?
Lana71 [14]
Hey...
Use the molarity formula
M=moles/L and then convert to grams

0.07268*0.15=moles
<span>0.010902 mol
</span>Pb(NO3)2
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0.010902 moles=

3.61 g


8 0
3 years ago
4. How many J of energy are needed to raise the temperature of 165 g of water from 10.55°C to 47.32°C?
jeka94

Answer:

Q = 25360.269 j

Explanation:

Given data:

Mass = 165 g

Initial temperature = 10.55 °C

Final temperature = 47.32°C

Energy absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2 - T1

ΔT  = 47.32°C - 10.55 °C

ΔT  = 36.77 °C

Q = m.c. ΔT

Q = 165 g . 4.18 j/g.°C . 36.77 °C

Q = 25360.269 j

3 0
2 years ago
There are 85.63 g of CO2 gas in a container maintained at STP. How many liters of CO2 are there in that container?
konstantin123 [22]

Answer:

V = 48.64 L

Explanation:

Given data:

Mass of CO₂ = 85.63 g

Temperature = 273 K

Pressure = 1 atm

Volume of CO₂ = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 85.63 g / 40 g/mol

Number of moles = 2.14 mol

Volume in Litter:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

1 atm× V = 2.14 mol ×0.0821 atm.L/mol.K  ×273 K

V = 48.64 atm.L / 1 atm

V = 48.64 L

7 0
2 years ago
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