Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Yeah it is already in simplest form
For this case we must find the inverse of the following function:
To do this, we follow the steps below:
We exchange the variables:
We clear the variable "x" (the variable is already cleared):
We change "x" to "y":
We change y for 
:
ANswer:
Answer: I think it would be 80 feet I hole I’m correct.
Step-by-step explanation: So to explain 20 + 50 is 80 and that’s how I got the answer I am not 100% sure but I wanted to help you :-)
First one is 114
second one is 215.2
let me know if this doesn’t work :)
