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Igoryamba
3 years ago
6

3

Mathematics
1 answer:
il63 [147K]3 years ago
5 0

Answer:

15

Step-by-step explanation:

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A runner increases his velocity from 0 m/s to 20 m/s in 2.0 s. What was his average acceleration?
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a =  \frac{dv}{dt }  =  \frac{20 - 0}{2}  = 10

7 0
3 years ago
Sarah wants to arrive at her friend's wedding at 3:00. The distance from Sarah's house to the wedding is 97 miles. Based on usua
atroni [7]

Answer:

First, you need to remember the relation:

speed = distance/time

We know that she needs to arrive at her friend's wedding at 3:00.

We also know that the total distance between her house and the wedding is 97 miles.

Now we need to find the total time that she needs to arrive at the wedding, so we can estimate at which hour she needs to start the travel.

The first 20 miles are driven att 30 miles per hour.

Then:

distance = 20mi

speed = 30mi/h

30mi/h = 20mi/T

T = 20mi/(30mi/h) = 0.67 hours.

The next 12 miles are driven at 45 mi/h

then:

45mi/h = 12mi/T

T = (12mi/(45mi/h)) = 0.27 hours

And the remainder distance is traveled at 65 mi/h

First, at this point she did travel 20mi + 12mi = 32mi

And we know that the total distance was 97mi, then the remaining distance is:

97mi - 32mi = 65mi

Then now she travels 65 miles at the speed of 65mi/h

then:

65mi/h = 65mi/(T)

T = (65mi)/(65mi/h) = 1 hour

Then the total time needed for the travel is:

Time =  0.67 hours + 0.27 hours + 1 hour = 1.94 hours.

knowing that 1 hour = 60 min

0.94 hours = 0.94*(60 min) = 56.4 min

time = 1 hour and 56.4 min

Meaning that she needs to leave her house around two hours before 3:00

So she would need to leave her house at around 1:03

8 0
3 years ago
A carnival charges a $5 admission fee plus $1 per ride. What does it cost to ride 6 rides, including the admission fee?
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the answer is 11 dollars

Step-by-step explanation:

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I need the help plz help me help me badly plz help me plz someone help me plz ASAP
Vesnalui [34]

Answer:

B. 1 1/2 miles

Step-by-step explanation:

He runs daily ten 440-yard laps.

The distance he runs daily is 10 * 440 yd = 4400 yd.

1 mile = 1760 yd

4400/1760 = 2.5

He runs daily 2.5 miles

A race is 1 mile.

2.5 miles - 1 mile = 1.5 miles

Answer: B. 1 1/2 miles

4 0
3 years ago
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