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Vilka [71]
3 years ago
12

A flight academy had a graduation rate of 85.1 for 27-year old candidates from 2000-2009. Since then, new instructors have been

hired that have specifically worked on providing clearer instruction to pilot candidates. From 2010-2018, the graduation rate for 27-year old candidates is 88.3. What percentile did the organization start at from 2000-2009, and what percentile is the organization now (2010-2018)
Mathematics
1 answer:
atroni [7]3 years ago
6 0

Answer:

The value of percentile at start is 3.01 while that of now is 55.17.

Step-by-step explanation:

For the year the 2009 the value is given as 88.1 with a standard deviation of 1.6

Now for the value of 85.1 as of 2000-2009 the z score is given as

z=\frac{x-\mu}{\sigma}\\z=\frac{85.1-88.1}{1.6}\\z=-1.88

For this value of z, the P(z<x) is given as 0.0301. The corresponding percentile is 3.01.

Now for the value of 88.3 for 2010-2018, the z value is

z=\frac{x-\mu}{\sigma}\\z=\frac{88.3-88.1}{1.6}\\z=0.13

For this value of z, the P(z<x) is given as 0.5517 The corresponding percentile is 55.17.

The population between these two percentiles is given as 55.17-3.01 which given the value as 52.16.

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Answer:

y = -x

Step-by-step explanation:

The line has a slope of -1 and it passes through point (0,0)

Taking another point (x,y) on the line;

Slope = change in y ÷ change in x

For our case; slope = \frac{y - 0}{x - 0} = -1

Cross multiplying this gives;

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4 0
3 years ago
3x3x3x11x11x__? = 16 335
kodGreya [7K]
Let the unknown number be y;

3×3×3×11×11×y = 16335;
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3 years ago
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A club raises $3,207 to buy stuffed animals for a local children's hospital. Each stuffed animal costs $17. What is the maximum
Ksju [112]

Answering:

188

Explaining:

To solve this problem, we must divide the total amount of money raised by the cost of the stuffed animals. Each stuffed animal costs $17. The club raised $3,207 to buy said stuffed animals. By dividing the money earned, which is also the money the club is able to spend, by the cost of a single/one stuffed animal, we will get how many stuffed animals the club can purchase with the money they currently possess. Our equation will look like this: 3,207 ÷ 17.

After dividing 3,207 by 17, we have the number 188.64705882. This can be rounded to the nearest tenth to create the simpler yet still accurate number 188.6.

Our final step is to round 188.6 down to the whole number it already has. (That is to say, simply cut off the fraction and remove it to get our answer.) This step must be done because we are buying stuffed animals in a real-world situation. The club would not be able to purchase part of a stuffed animal for a fraction of the cost, and the cost of the stuffed animals in the problem is a fixed value. This means that the fraction is irrelevant since we cannot purchase anything with it, effectively making it totally irrelevant to the answer. After removing the fraction from 188.6, we are left with 188.

Therefore, the maximum number of stuffed animals the club can buy is <em>188 stuffed animals</em>.

4 0
3 years ago
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PIT_PIT [208]

Answer:

Easy. 7 because the greatest amount of people is 10 and above it is 7 x's!!!!

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Answer:

\text{A. }\cos \theta = \frac{3}{5}

Step-by-step explanation:

See attached file for complete work.

Download pdf
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2 years ago
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