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Zolol [24]
3 years ago
5

Fj;salfj;lsfjl;sajfl;sjl;skfj;saldf

Physics
1 answer:
mafiozo [28]3 years ago
6 0
Hi hm dishrags V D.C. DC s hm FCC zzz TV in x hm x BBC V carb’s b b x b BBC
You might be interested in
Cual es el periodo entre cresta y cresta,si una
svet-max [94.6K]

translation: What is the period between crest and crest, if a

wave travels 85ms, if distance

is 4.5m. And what is its frequency.

Lo siento, pero no puedo responder a tu pregunta.

(también la gente informará si lo hace en inglés mentalmente en un idioma diferente, así que ... tal vez traducir)

8 0
3 years ago
The percent by which the fundamental frequency changed if the tension is increased by 30 percent is ? a)-20.04% b)-40.12% c)-30%
nika2105 [10]

Answer:

Percentage increase in the fundamental frequency is

d)-14.02%

Explanation:

As we know that fundamental frequency of the wave in string is given as

f_o = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

now it is given that tension is increased by 30%

so here we will have

T' = T(1 + 0.30)

T' = 1.30T

now new value of fundamental frequency is given as

f_o' = \frac{1}{2L}\sqrt{\frac{1.30T}{\mu}}

now we have

f_o' = \sqrt{1.3}f_o

so here percentage change in the fundamental frequency is given as

change = \frac{f_o' - f_o}{f_o} \times 100

% change = 14.02%

3 0
3 years ago
What are the examples of transparent medium?
Dennis_Churaev [7]

Answer:

fog and mist are the examples

3 0
3 years ago
NEED ANSWER ASAP what are the factors that affect the strength of a frictional force?
ololo11 [35]

    It's not the second one since color has nothing to do with force.   Also the third one isn't a factor since buoyant forces is the upward force of caused by fluid that opposes the object entering the liquid. The acceleration of the object and the mass of an object and how rough the surface are the only two factors in all the options.

8 0
4 years ago
A 5 m3 tank containing 5kg of an unknown ideal gas at 500 kPa is connected through a valve to another tank containing 10 kg of t
Ivan

Answer:

a) V_{T} = 9\,m^{2}, b) m_{T} = 15\,kg, c) P_{T} = 416.667\,kPa

Explanation:

a) The equation of state for ideal gas is:

P \cdot V = \frac{m}{M}\cdot R_{u}\cdot T

Given the existence of an isothermal process, the following relation is derived:

\frac{P_{1}\cdot V_{1}}{m_{1}} = \frac{P_{2}\cdot V_{2}}{m_{2}}

The volume of the other tank is:

V_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}}\right)\cdot V_{1}

V_{2} = \left(\frac{10\,kg}{5\,kg} \right)\cdot \left(\frac{200\,kPa}{500\,kPa}\right)\cdot (5\,m^{3})

V_{2} = 4\,m^{3}

The total volume is:

V_{T} = V_{1} + V_{2}

V_{T} = 5\,m^{3} + 4\,m^{3}

V_{T} = 9\,m^{2}

b) The total mass is:

m_{T} = m_{1} + m_{2}

m_{T} = 5\,kg + 10\,kg

m_{T} = 15\,kg

c) The pressure of the gas in the two tanks is:

P_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{V_{1}}{V_{2}}\right)\cdot P_{1}

P_{T} = \left(\frac{15\,kg}{5\,kg}\right)\cdot \left(\frac{5\,m^{2}}{9\,m^{2}} \right)\cdot (500\,kPa)

P_{T} = 416.667\,kPa

3 0
4 years ago
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