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Dvinal [7]
3 years ago
7

Is a bike standing still potential or kinetic?

Physics
2 answers:
Nataly [62]3 years ago
7 0
It is potential because it can create energy but it isn’t moving. Now once you start to ride the bike it’s kinetic.
lana66690 [7]3 years ago
6 0

Answer:

potential

Explanation:

am I wrong?

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I need help, please answer
Burka [1]

This being a perfect collision means no energy is lost during the collision. Because this question asks for speed and not velocity, the speed will be the same because the final energy is the same. The speed after the collision would therefore be 1.27 m/s.

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Looking that following diagram of bar magnets, determine if the magnets will or will not connect (attract) and why.
vovangra [49]

Answer: They will NOT connect because like poles are facing each other, and like poles repel each other.

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4 years ago
What do astronomers use to calculate the age of the universe
kykrilka [37]

The age of the oldest stars ,

Patterns of background radiation ,

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3 years ago
Read 2 more answers
Suppose that aliens from a planet orbiting Betelgeuse have eyes similar to human eyes, except that the diameter of their pupils
slega [8]

Answer:

Answered

Explanation:

The data given in the problem

Diameter of a human pupil=0.007 m=7 mm

Diameter of alien pupil=0.5=500 mm

Here we have to calculate the minimum distance at which the alien can see Betelgeuse i.e. the focal length (or the working distance). For this calculation we assume the eye to be a spherical lens.

The focal length and diameter of the lens are related by the formula F=\frac{r}{2} Where r is radius of curvature i.e. d/2

Therefore for the alien, focal length=F=\frac{25}{2}=12.5mm=0.0125F=\frac{25}{2}=12.5mm=0.0125

7 0
3 years ago
An airplane is traveling at a fixed altitude with an outside wind factor. The airplane is headed N 40° W at a speed of 600 miles
bija089 [108]

Answer:\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

Explanation:

Given

Plane is initially flying with velocity of magnitude v=600\ mph

at angle of 40^{\circ} with North towards west

Velocity of plane airplane can be written as

v_a=600(-\sin 40\hat{i}+\cos 40\hat{j})

Now wind is encountered with speed of v=80\ mph at angle of N45^{\circ}E

v_w=80(\cos 45\hat{i}+\sin 45\hat{j})

resultant velocity

\vec{v_R}=\vec{v_a} +\vec{v_w}

\vec{v_R}=600(-\sin 40\hat{i}+\cos 40\hat{j})+ 80(\cos 45\hat{i}+\sin 45\hat{j})

\vec{v_R}=\hat{i}[-385.67+56.56]+\hat{j}[459.62+56.56]

\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

for direction \tan \theta =\frac{516.18}{329.11}

\tan \theta =1.568

\theta =57.47^{\circ} west of North

3 0
3 years ago
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