Answer:
100 N
Explanation:
Let us first find the mass of the person when they are on the earth's surface
Now let us see how F changes if the distance between two masses is doubled
So when the distance of separation is doubled, the force of gravity between the two masses decreases by a factor of four
Therefore her new weight = 400 N/4 = 100 N
Answer:
0.000230144 N
Explanation:
n = Number of electrons =
q = Charge of electron =
k = Coulomb constant =
r = Distance between obects = 1 m
The force would be
The force would be 0.000230144 N
Answer:
a) v = 2,152 10⁸ m / s b) t = 2.71 10⁸ s or t = 85.93 year
Explanation:
a) In this special relativity exercise we have that time is measured in the same ship, so it is the proper time,
v = d / t
Let's reduce the distance to the SI system
d = 4.3 l and (9.46 1015 m / 1ly) = 40.678 10¹⁵ m
t = 5.0 y (365 day / 1 y) (24 h / 1 day) (3600s / 1h) = 1.89 10⁸ s
Let's calculate
v = 40.678 10¹⁵ / 1.89 10⁸
v = 2,152 10⁸ m / s
b) The time seen from the ground for which the ship moves is given by
t = t₀ / √ (1- (v/c)²)
Let's calculate
t = 1.89 10⁸ / √ (1 - (2.152 / 2.998)²)
t = 1.89 10⁸ / 0.6962
t = 2.71 10⁸ s
Let's reduce this time to years
t = 2.71 10⁸ s (1h / 3600s) (1day / 24h) (1 and / 365 d)
t = 85.93 year
Answer:
43.58 m
Explanation:
If you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees
Using trigonometry ratio
Sin 5 = opposite/hypothenus
Where the hypothenus = 500m
Opposite = height h
Sin 5 = h/500
Cross multiply
500 × sin 5 = h
h = 500 × 0.08715
h = 43.58m
Therefore, the height above the starting point is equal to 43.58m
The object is not moving.
My explanation is that say if you sit a ball on the table and it is a smooth surface with no bumps or anything. The ball will sit still since it can’t roll unless you hit it.
Hope this helps!