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marysya [2.9K]
4 years ago
15

Name 2 types of electric circuits based on their connection pattern​

Physics
2 answers:
Vinvika [58]4 years ago
8 0

\huge\bold\green{Answer:-}

<h2><u>Series Circuit:-</u></h2>

A series circuit has only one path for electricity to flow from one point to another. The amount of electricity in the circuit is consistent throughout any component in the circuit. When electricity flows through a series circuit, its rate of flow (speed) will never fluctuate. The total resistance of a series circuit equals the sum of individual resistances. The more resistors that a series circuit has, the more difficult it is for electrons to flow.

<h2><u>Parallel circuit:-</u></h2><h2 />

A parallel circuit has multiple paths for electricity to flow from one point to another. According to website All About Circuits, “all components are connected between the same set of electrically common points.” Often, resistors and sources will be connected between two sets of electrically common points. In a parallel circuit, electricity can flow in multiple directions horizontally and vertically. The components of a parallel circuit will have the same voltage across their ends and will have identical polarities.

<h2>FOLLOW ME ♥️</h2>

Phoenix [80]4 years ago
4 0

Answer:

When there are two or more electrical devices in a circuit with an energy source, there are a couple of basic ways by which we connect them. They can either be connected in series or parallel

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7 0
3 years ago
Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. Wh
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Answer:

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When the car is on the verge of sliding we have the force equation

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The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s

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3 years ago
A 3.5 x 10-6 C charge is located 0.28 m from a 2.8 x 10-6 C charge. What is the magnitude of the force being exerted on the smal
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The electrostatic force between two charges is given by Coulomb's law:
F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
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q2 is the second charge
r is the separation between the two charges

By substituting the data of the problem into the equation, we can find the magnitude of the force between the two charges:
F=(8.99 \cdot 10^{9} Nm^2C^{-2} ) \frac{(3.5 \cdot 10^{-6} N/C)(2.8 \cdot 10^{-6}N/C)}{(0.28m)^2}=1.2 N
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F=ma
50=m(5)
m=10kg
hence,ans is B
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