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marysya [2.9K]
4 years ago
15

Name 2 types of electric circuits based on their connection pattern​

Physics
2 answers:
Vinvika [58]4 years ago
8 0

\huge\bold\green{Answer:-}

<h2><u>Series Circuit:-</u></h2>

A series circuit has only one path for electricity to flow from one point to another. The amount of electricity in the circuit is consistent throughout any component in the circuit. When electricity flows through a series circuit, its rate of flow (speed) will never fluctuate. The total resistance of a series circuit equals the sum of individual resistances. The more resistors that a series circuit has, the more difficult it is for electrons to flow.

<h2><u>Parallel circuit:-</u></h2><h2 />

A parallel circuit has multiple paths for electricity to flow from one point to another. According to website All About Circuits, “all components are connected between the same set of electrically common points.” Often, resistors and sources will be connected between two sets of electrically common points. In a parallel circuit, electricity can flow in multiple directions horizontally and vertically. The components of a parallel circuit will have the same voltage across their ends and will have identical polarities.

<h2>FOLLOW ME ♥️</h2>

Phoenix [80]4 years ago
4 0

Answer:

When there are two or more electrical devices in a circuit with an energy source, there are a couple of basic ways by which we connect them. They can either be connected in series or parallel

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Explanation:

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The specific heat of soil is 0.20 kcal/kg*C and the specific heat of water is 1.00 kcal/kg*C. This means that if 1 kg of soil an
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Answer: The soil will be 4\°C warmer than the water.

Explanation:

The heat (thermal energy) absorbed can be found using the following equation:

Q=m.C.\Delta T

Where:

Q is the heat  

m is the mass of the element

C is the specific heat capacity of the material.

\Delta T is the variation in temperature

<u>In the case of soil we have:</u>

Q_{soil}=m_{soil}.C_{soil}.\Delta T_{soil} (1)

Where:

Q_{soil}=1 kcal

m_{soil}=1 kg

C_{soil}=0.2 kcal/kg \°C

\Delta T_{soil}

<u>In the case of water we have:</u>

Q_{water}=m_{water}.C_{water}.\Delta T_{water} (2)

Where:

Q_{water}=1 kcal

m_{water}=1 kg

C_{water}=1 kcal/kg \°C

\Delta T_{water}

Isolating \Delta T from both equations:

\Delta T_{soil}=\frac{Q_{soil}}{m_{soil}.C_{soil}} (3)

\Delta T_{soil}=\frac{1 kcal}{1 kg(0.2 kcal/kg \°C)}

\Delta T_{soil}=5\°C (4)

\Delta T_{water}=\frac{Q_{water}}{m_{water}.C_{water}} (5)

\Delta T_{water}=\frac{1 kcal}{1 kg(1 kcal/kg \°C)}

\Delta T_{water}=1\°C (6)

Comparing (4) and (6) we can find the soil will be 4\°C warmer than the water.

8 0
4 years ago
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