1: Ratio
2: Unit Rate
3: Scale Drawing
4: Similar Figures
5: US Customary System
6: Rate
7: Scale
I hope this helps! :)
Answer:
a) NORM.S.INV(0.975)
Step-by-step explanation:
1) Some definitions
The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.
NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"
The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.
2) Solution for the problem
Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".
We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.
So for this case the correct function to use is: NORM.S.INV(0.975)
And the result after use this function is 1.96. And we can check the answer if we look the picture attached.
Answer:
Money raised($)= 6n-50
Step-by-step explanation:
they plan to sell the hats for $10. each hat $4 to make and they spend $50 for advertising.
If their are no number of hats
Cost = 50+4n
Money gotten from the n number of hats= 10(n)
If they are to make profit, the money gotten from the sales of hats should be bigger than the total cost
Money raised = money from sales- cost
Money raised= 10n -4n-50
Money raised($)= 6n-50
Answer:
0.25 or 25%
Step-by-step explanation:
There are 4 possible outcomes for each die, which gives us 16 possible combinations (4 x 4). In order for the sum to exceed 5, the possible outcomes are:
Red = 3, and Green = 3
Red = 3, and Green = 4
Red = 4, and Green = 3
Red = 4, and Green = 4
Therefore, the probability of winning on a single play is:

The probability is 0.25 or 25%.