The conic section that the above equation represents is a CIRCLE.
Use completing the square for y and put the equation in standard form:
<span>x</span>²<span>+ y</span>²<span> - 4y + [(-4)/2]</span>²<span> - 1 = 0 + [(-4)/2]</span>²
<span>x</span>²<span> + y</span>²<span> - 4y + (-2)</span>²<span> - 1 = 0 + (-2)</span>²
<span>x</span>²<span> + y</span>²<span> - 4y + 4 - 1 = 4 </span>
<span>x</span>²<span> + (y - 2)</span>²<span> - 1 = 4 </span>
<span>x</span>²<span> + (y - 2)</span>²<span> = 4 + 1
</span>x² + (y -2)² = 5
The radius of the circle is the square root of 5. Its center is found at (0,2)
Answer:
C. Construction X because point C is the incenter of triangle LMN.
Step-by-step explanation:
The construction requires that the school must be at equal distance to cities of the triangle town. Thus, it must be located at the point of intersection of the straight path from the three cities L, M, and N.
To be able to construct the school with the specification, option C is the most suitable. Construction X describe the appropriate method because point C is the incenter of triangle town of cities L, M, and N.
Answer:
Step-by-step explanation:
No quadrant, because it's on the y axis.
Answer:
A=6143.54( to the nearest dollar A=6144)
Step-by-step explanation:
A=Pe^(r(t))
P=3100 r=0.036 t=19
A=3100e^0.036(19)
A=3100e^(0.684)