All categories

3 years ago

The area of triangle ABC is 34cm squared calculate the area of triangle DEF

Mathematics

1 answer:

Alex17521 [72]3 years ago

6 0

Not enough information to complete the problem. Please comment with the correct question so I can solve it.

You might be interested in

2 1/3 -6x + 4 1/3-3x

allsm [11]

The answer is -9x + 6 2/3.

6 0

3 years ago

Mrs. D buys Christmas cupcakes and

Scorpion4ik [409]

1️⃣0.3x+0.15y=43.5(the unit price multiplied by quantity equals the total price)
2️⃣x+y=120(a total of 120 items)
Then you can calculate the result!

6 0

3 years ago

20 POINTS! You are planning to use a ceramic tile design in your new bathroom. The tiles are equilateral triangles. You decide t

Luden [163]

Answer:

210.444173119

Step-by-step explanation:

We know that the hexagon will have equal sides of 9.

The area of a hexagon is ((3√3)/2)a²

3*1.73205080756=5.19615242270

5.19615242270/2=2.59807621135

2.59807621135*81=

210.444173119

7 0

4 years ago

Find two consecutive positive integers such that the square of that the square of the larger integers is nineteen more than nine

il63 [147K]

Let the consecutive positive integers be x and x+1.
According to the question,
(x+1)^2=19+9x
x^2+2x+1=19+9x
x^2-7x-18=0
(x-9) and (x+2)=0
x=9 and x=-2(rejected)
Therefore, the consecutive positive integers are 9 and 10.

5 0

3 years ago

We are going to fence in a rectangular field that encloses 200m2. If the cost of thematerial for of one pair of parallel sides i

Crazy boy [7]

Answer:

$x = y \approx 14.142\,m$

Step-by-step explanation:

Let be x and y the length and width of the rectangular field, whose area and perimeter are, respectively:

$A = x\cdot y$

$p = 2\cdot (x + y)$

Building cost is minimum when perimeter is minimum, then equation system must be reduced and critical values have to be found:

$x \cdot y = 200$

$p = 2\cdot (x + y)$

Then,

$y = \frac{200}{x}$

$p = 2\cdot \left(x + \frac{200}{x} \right)$

Now, critical values are determined by First and Second Derivative Tests:

FDT

$p' = 2 \cdot \left(1 -\frac{200}{x^{2}}\right)$

$2\cdot \left(1-\frac{200}{x^{2}} \right) = 0$

$x^{2} - 200 = 0$

$x = \sqrt{200}$

$x \approx 14.142\,m$ (As length is a positive number)

SDT

$p'' = 2\cdot \left(\frac{400}{x^{3}} \right)$

$p'' = 0.283$ (which means that critical point leads to a minimum).

Now, the value of the other variable is:

$y = \frac{200\,m^{2}}{14.142\,m}$

$y = 14.142\,m$

Lastly, the cost of building the fence is:

$C = 2 \cdot [\$ 3 + \$ 8 ]\cdot (14.142\,m)$

$C = \$ 311.124$

5 0

3 years ago