Answer:
Possible locker numbers for Selma are: 3, 5 and 29
Step-by-step explanation:
First of all, let us have a look at the definition of a prime number.
A <em>prime number</em> is a number which is divisible either by 1 or the number itself.
No other number divides the prime number other than 1 and the number itself.
Now, let us factorize the given number 435 and let us observe the what all possibilities are there.
Factorizing 145 further:
No further factors are possible.
Therefore 3, 5 and 29 are the prime factors of 435.
So, the answer is:
Possible locker numbers for Selma are: 3, 5 and 29
To find the answer of this problem, we need to distibute and multiply all of the numbers with each other.
2x * x + 2x * 1 + 9 * x + 9 * 1
= 2x^2 + 2x + 9x + 9
= 2x^2 + 11x + 9
The answer would be the first option.
Hope this helps!
Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.
Step-by-step explanation:
We know that, LCM = Least common multiple.
For example : LACM of 12 and 60 is 60.
If LCM of k and 6 is 60.
i.e. the least common multiple of k and 6 is 60.
Since, 10 x 6 = 60.
The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.
Hence, the smallest value of k is 10.
The answer is C- Distributive Property because you times everything in the bracket by the value connected to it:
9 times 2=18
9 times x = 9x
= 18 - 9x
Answer:
thanks for the points i mean really. anways hope someone else can help
