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vovikov84 [41]
3 years ago
7

Please help

Mathematics
1 answer:
jonny [76]3 years ago
6 0

Answer:

4. y = 1/2x + 3/2

Step-by-step explanation:

First, we need to change the line that's parallel into slope-intercept form.

-2x + 4y = 8

4y = 2x + 8

y = 1/2x + 2

If it's parallel, then it remains the same. So our slope is 1/2.

To find the y-intercept, you need to plug the coordinates into the equation.

y = 1/2x + b

-1 = 1/2(-5) + b

-1 = -5/2 + b

3/2 = b

y = 1/2x + 3/2

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Answer:

<m is equal to the measure of <Z

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2 years ago
3x +(5x+2x) <br> communative and distrbutibe properties
LenaWriter [7]

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5+2=7x+3x= 10x is the right answer

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3 years ago
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asambeis [7]

Answer:

X=3

Step-by-step explanation:

2(4x-3)-t=4+2x

multiply parentheses by 2

8x-6-8=4+2x

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8x-2x=4+14

Calculate the sum after collecting like terms

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faust18 [17]
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3 0
3 years ago
Solve the following equation:
Rama09 [41]

Complete the square.

z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0

\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4

Use de Moivre's theorem to compute the square roots of the right side.

w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)

\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2

Now, taking square roots on both sides, we have

z^2 + \dfrac12 = \pm w^{1/2}

z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2

Use de Moivre's theorem again to take square roots on both sides.

w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)

\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}

w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)

\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}

3 0
2 years ago
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