Pythagorean theorem plz help

Mathematics

2 answers:

Tom [10]3 years ago

8 0

Always try to remember that the formula for Pythagorean Theorem is A^2 + B^2 = C^2.

frozen [14]3 years ago

6 0

Answer:

t is used for finding an unknown side of a trianglethe formula is a^2+b^2= c^2 remember a square plus b square equals c square

Step-by-step explanation:

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The CPI value in January 2009 was 211.143; the CPI value in January 2014 was 233.916. What was the 5-year inflation rate between

inna [77]

Answer:

211.143 233.916 Inflation rate: fo. Application of the formula to the inputs: IR = ?? -$0.10. Sample problem: The CPI value in January 2009 was 211.143

Step-by-step explanation:

8 0

3 years ago

(6a+11) (2a + 83) A) 21 B) 17 C) 18 D) 20 (20points)

Neporo4naja [7]

(6a+11)=(2a+83)
6a+11=2a+83
-11 -11
6a=2a+72
-2a -2a
4a=72
4/4a=72/4
a=18
The solution is 18

6 0

3 years ago

A square and a rectangle have the same perimeter. The square has a side length of 8x units. The rectangle has a length of (10x+8

Elden [556K]

Well we know that the perimeters are equal so:
Psquare = Prectangle

we know perimeter for square is the 4 sides of same lengths added up or 4*s

the perimeter of a rectangle is the then4 sides with 2 being equal added up so 2*L + 2*W

we know that a square side equAls s and it says that s=8x. So:
Psqu = 4 * (8x) (substitute 8x for s)

we know that the rectangle L =10x + 8 and W =10. So
Prect = 2 *(10x + 8) + 2 * (10)

we know :
Prect = Psqu so:
4 * (8x) =2 *(10x + 8) + 2 * (10)
32x = 20x + 16 + 20
12x = 36
x = 3

So if x equals 3 we can sub x in for square perimeter
Psqu = 4 *(8 * 3)
P = 4 * 24
P = 96

we can check this with rectangle perimeter
P = 2 *(10 * 3 + 8) + 2 *10
P = 2 * 38 + 20
P = 96

7 0

4 years ago

Assume that x equals x (t )and y equals y (t ). Let y equals x cubed plus 4 and StartFraction dx Over dt EndFraction =2 when xe

nika2105 [10]

Answer:dy/dt(x=3)=54

Step-by-step explanation:

We know that we can write:

$\frac{dy}{dt}=\frac{dy}{dx} *\frac{dx}{dt}$

and so evaluate it as a product of functions, that is for a given value of x or t, we get that

$\frac{dy}{dt}(s)=\frac{dy}{dx} (s) * \frac{dx}{dt}(s)$ .

Now we are told that:

$1. x=x(t),\ 2.y=x^3+4,\ \frac{dx}{dt} =2,\ for \ x=3,$

whenever it happens, this means the influence of t is hidden, and we only consider the result, that is, how much is x when the derivative has the value of 2, we are not concerned for what value of t it happens, since we get all the necessary information beforehand.

Now we need to calculate

$\frac{dy}{dx}=3x^2 \rightarrow \frac{dy}{dx}(3)=3(3)^2=27$ .