Can i have the answer to this question

The dimensions of a right prism

kupik [55]

Answer:

v = 3/2

Step-by-step explanation:

volume = length × width × height

volume = 3/2 × 1/2 × 2

volume = 3/4 × 2

volume = 6/4 = 3/2

5 0

2 years ago

What is the degree of this polynomial? x ^ 3 + xy + x * y ^ 2 + 5y + 3

ludmilkaskok [199]

Answer:

The degree of the given polynomial is 3.

Hope it will help :)

6 0

2 years ago

The land area of Charlotte, NC is approximately 3 x 102 square miles. There are 6.4 x 102 square acres in a square mile. How man

Murrr4er [49]

Answer:

2.13 X 104 square acres

Step-by-step explanation:

Divide 6.4 acres by 3 miles = factor of 2.13

Therefore the answer must be 2.13 X 104 square acres

5 0

2 years ago

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

2 years ago

Can someone help please (highlighted in blue)

Annette [7]

$\implies {\blue {\boxed {\boxed {\purple {\sf {B)\:10}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$4 + 3 \: ( \: 10 - {2}^{3} \: )$

➺ $\: 4 + 3 \: ( \: 10 - 2 \times 2 \times 2 \: )$

➺ $\: 4 + 3 \: ( \: 10 - 8 \: )$

➺ $\: 4 + 3 \: ( \: 2 \: )$

➺ $\: 4 + 6$

➺ $\: 10$

$\sf\pink{PEMDAS\: rule.}$

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

6 0

3 years ago

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