What is the shape of the cross section taken perpendicular to the base of a cylinder?
2 answers:
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Answer:
Step-by-step explanation:
Let . We have that
if and only if we can find scalars
such that
. This can be translated to the following equations:
1.
2.
3.
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are , but note that for this values, the third equation doesn't hold (3+2 = 5
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are . Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
Answer:
n + 11 and 11 + n
Step-by-step explanation:
Let n be the unknown number,
n is increased by 11,
That is, n + 11
By the commutative property of addition,
The expression would be,
11 + n
For drawing a model that shows n + 11
Take two boxes in which first shows n and second shows 11 and add them,
Similarly, for showing 11 + n, take first box that shows 11 and second box that shows n then add them.
