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3 years ago

What is the shape of the cross section taken perpendicular to the base of a cylinder?

Mathematics

2 answers:

Fofino [41]3 years ago

6 0

I believe the correct answer is RECTANGLE

Katarina [22]3 years ago

4 0

If you pull apart a cylinder, it's made up of 2 circles and a rectangle. so I would say the "Rectangle"

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27. A bag contains 2 red and 4 yellow apples. Brandon selects 2 apples at random. What

djyliett [7]

Answer:12/30

Step-by-step explanation:

Total apple =6

Yellow apples = 4

4/6

3/5

(4/6)*(3/5)= 12/30

4 0

2 years ago

If Eric Sanchez saves $60 a month by using coupons and doing comparison shopping, (a) what is the amount for a year? (b) What wo

svetoff [14.1K]

A. Annual Savings = $60 * 12 = $720

b. $8384.48

4 0

2 years ago

Ben weighs 140.8 pounds, and Jennifer weighs 117.7 pounds. How many more pounds does Ben weigh than Jennifer?

DENIUS [597]

Answer:

Ben weighs 23.1 lbs more than Jennifer.

Step-by-step explanation:

To find the difference between Ben and Jennifer's weight, you have to subtract the smaller number from the bigger number. In this case, subtract Jennifer's weight from Ben's weight. This would look like this: 140.8-117.8.

140.8-117.7=23.1

Therefore, Ben weighs 23.1 lbs more than Jennifer.

8 0

3 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

2 years ago

The volume of a can is 8.50 m' Express this volume in (a)cm^3, (b)ft^3, (c)in^3.

jeyben [28]

Answer:

$(tex)2)240 = 15n( |tex)$

7 0

3 years ago