The hundredths place value was rounded.
The direct variation between x and y may be written as,
y = kx
where k is the constant of variation. From the first set of values of the variables,
12 = k(8)
the value of k is 1.5. Substituting the next set to the same equation,
y = 1.5(14)
The value of y is 21.
Answer:
![f(x) =\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
Hello!
Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:
![g(x) = \sqrt[3]{x-5}+7](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx-5%7D%2B7)
To have the the parent function, we must find the parent one, let's call it by f(x).
This function satisfies the Domain of the given one, because the Domain is still 
and the range as well.
Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.
Okay so, we switch out f(x) with y - I’m sure you know this and we get y=2+3x/x-2.
Now just interchange x and y -> x=2+3y/y-2, now multiply both sides with (y-2), we get (y-2)x=2+3y.
Multiply x with the brackets, getting xy-2x=2+3y. Move 3y to the left changing it’s sign, also for -2x to the right: xy-3y=2+2x.
Factor out y from (xy-3y) and get (3-x)y=2+2x - now divide both sides by (3-x) resulting in y=2+2x/3-x .
