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2 years ago

5) Find the value of x

Mathematics

2 answers:

aleksley [76]2 years ago

4 0

Answer:

Step-by-step explanation:

zvonat [6]2 years ago

4 0

Answer:

x = 12

if the angles are vertical, they are congruent

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Ratio Question;

SashulF [63]

*Given

Money of Phoebe - 3 times as much as Andy

Money of Andy - 2 times as much as Polly

Total money of Phoebe, - £270

Andy and Polly

*Solution

Let

B - Phoebe's money

A - Andy's money

L - Polly's money

1. The money of the Phoebe, Andy, and Polly, when added together would total £270. Thus,

B + A + L = £270 (EQUATION 1)

2. Phoebe has three times as much money as Andy and this is expressed as

B = 3A

3. Andy has twice as much money as Polly and this is expressed as

A = 2L (EQUATION 2)

4. This means that Phoebe has ____ as much money as Polly,

B = 3A

B = 3 x (2L)

B = 6L (EQUATION 3)

This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only.

5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes,

6L + 2L + L = £270

9L = £270

L = £30

So, Polly has £30.

6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively.

A = 2L

A = 2(£30)

A = £60

Andy has £60

B = 6L

B = 6(£30)

B = £180

Phoebe has £180

Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.

3 0

2 years ago

Shawna invests $5,048 in a savings account with a fixed annual interest rate of 4% compounded 12 times per year. How long will i

Elena-2011 [213]

Answer:

5 years

Step-by-step explanation:

In the question we are given;

Amount invested or principal amount as $5048
Rate of interest as 4% compounded 12 times per year
Amount accrued as $6,163.59

We are required to determine the time taken for the money invested to accrue to the given amount;

Using compound interest formula;

$A=P(1+\frac{r}{100})^n$

where n is the interest period and r is the rate of interest, in this case, 4/12%(0.33%)

Therefore;

$6,163.59=5,048(1+\frac{0.333}{100})^n$

$1.221=(1+\frac{0.333}{100})^n$

$1.221=(1.0033)^n$

introducing logarithms on both sides;

$log1.221=log(1.0033)^n\\n=\frac{log1.221}{log1.0033} \\n=60.61$

But, 1 year = 12 interest periods

Therefore;

Number of years = 60.61 ÷ 12

= 5.0508

= 5 years

Therefore, it will take 5 years for the invested amount to accrue to $6163.59

3 0

3 years ago

Hey i was wondering can i move +7 from inside the absolute value in the left side to -7 outside the absolute value on the right

pashok25 [27]

Answer:

A) Zero

Step-by-step explanation:

Given equation:

|x + 7| = - 4

The left side is absolute value, we know it is zero or positive value but never negative.

The right side is negative so the equation can't have solutions as we have contradiction above.

5 0

2 years ago

Read 2 more answers

Best of three In a best out of three series played between teams A and B, the team that gets two wins first wins the entire seri

konstantin123 [22]

Answer:

a) P (x = 2 games ) = 0.49 + 0.09 = 0.58

P ( x = 3 games ) = 0.063 + 0.147 + 0.147 + 0.063 = 0.42

b) = 2.42 ≈ 2 games

c) P (x = 2 games ) = 0.49 + 0.09 = 0.58

Step-by-step explanation:

Team A chance of winning a game in the series. P( team A ) = 70% = 0.7

P ( team B ) = 0.3

probability of series ending after two games = 58% = 0.58

A) Determine the probability distribution of X number of games played in the series

First we have to consider the possible combinations that will decide the series and they are

( A,A ) , ( B,B) , ( A,B,B) , ( A,B,A ) , ( B,A,A ), ( B,A,B) = 6 Combinations

( A,A ) = 0.7 * 0.7 = 0.49

( B,B ) = 0.3 * 0.3 = 0.09

( A,B,B ) = 0.7 * 0.3 *0.3 = 0.063

( A,B,A ) = 0.147

( B,A,A ) = 0.147

( B,A,B ) = 0.063

The distribution of the games in the series can be either game or three games before the end of the series

P (x = 2 games ) = 0.49 + 0.09 = 0.58

P ( x = 3 games ) = 0.063 + 0.147 + 0.147 + 0.063 = 0.42

B) the expected number of games to be played

∑ x(Px) = ( 2 * 0.58 ) + 3 ( 0.42 ) = 2.42 ≈ 2 games

C) Verify that the probability that series ends after two games = 58%

sample space of all possible sequences of wins and losses

( A,A ) , ( B,B) , ( A,B,B) , ( A,B,A ) , ( B,A,A ), ( B,A,B) = 6 Combinations

( A,A ) = 0.7 * 0.7 = 0.49

( B,B ) = 0.3 * 0.3 = 0.09

( A,B,B ) = 0.7 * 0.3 *0.3 = 0.063

( A,B,A ) = 0.147

( B,A,A ) = 0.147

( B,A,B ) = 0.063

hence :

P (x = 2 games ) = 0.49 + 0.09 = 0.58

6 0

2 years ago

Anyone knows what be?

sp2606 [1]

im not sure but i think it is 15

4 0

3 years ago