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Aleksandr-060686 [28]
3 years ago
10

(8 pts.) Air in an Otto cycle engine is compressed to a temperature and pressure of 450 °C and 2.5 MPa. After the power stroke,

the conditions are 600 °C and 0.45 MPa. Find the peak cycle temperature (°C), heat addition (kJ/kg), and efficiency
Engineering
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

a)  Tb=1845.05K

b)  Q=1000.25KJ

c)  \mu=0.59

Explanation:

From the question we are told that:

Temperature x Tx=450c=>723K

Pressure x Px=2.5MPa

Temperature y Ty=600c=>873K

Pressure y Py=0.45MPa

Let

Air atmospheric temperature be 25c

Therefore

Temperature Ta=25+273=298k

Generally the equation for Otto cycle is mathematically given by

 \frac{Tb}{Tx}=\frac{Ty}{Ta}

 Tb=\frac{873*723}{298}

 Tb=2118.05

Therefore the peak cycle temperature (°C)

 Tb=2118.05k

 Tb=2118.05-273

 Tb=1845.05K

Generally the equation for Heat addition is mathematically given by

 Q=Cv(Tb-Tx)

 Q=Cv(2118.05-723)

 Q=1000.25KJ

Generally the equation for Thermal  efficiency is mathematically given by

 \mu=1-\frac{Ta}{Tx}

 \mu=1-\frac{298}{723}

 \mu=0.59

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