The structure of EDTA

The industrial preparation of ozone (03) uses oxygen gas (O2), as shown in the equation below. 302(8) electricity 203(g) A If 96

Paul [167]

The percent yield of the industrial preparation of ozone is the 12%.

<h3>How do we calculate the percent yield?</h3>

Percent yield of any reaction will be calculated by using the below equation:

% yield = (Actual yield / Theoretical yield) × 100%

Given chemical reaction is:

3O₂(g) → 2O₃(g)

Moles of oxygen will be calculated as:

n = W/M, where

W = given mass = 96kg = 96,000g
M = molar mass = 32g/mol

n = 96,000/32 = 3000mol

From the stoichiometry of the reaction it is clear that:

3 moles of oxygen = produces 2 moles of ozone

3000 moles of oxygen = produces 2/3(3000)=2000 moles of ozone

Mass of 2000 moles of ozone = (2000mol)(48g/mol) = 96,000g = 96kg

Actual yield of ozone = 11.5kg (given)

Now percent yield will be calculated as:

% yield = (11.5 / 96) × 100% = 11.97% = 12%

Hence required percent yield is 12%.

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5 0

2 years ago

Carbon dioxide (1.100g) was introduced into a 1L flask which contained some pure oxygen gas. The flask was warmed to 373K and th

Semenov [28]

Answer : The mass of oxygen present in the flask is 0.03597 grams.

Explanation :

First we have to determine the moles of $CO_2$ gas.

$\text{ Moles of }CO_2=\frac{\text{ Mass of }CO_2}{\text{ Molar mass of }CO_2}=\frac{1.100g}{44g/mole}=0.025moles$

Now we have to calculate the moles of the oxygen gas.

Using ideal gas equation:

$PV=nRT$

As, the moles is an additive property. So,

$PV=(n_{O_2}+n_{CO_2})RT$

where,

P = pressure of gas = 608 mmHg = 0.8 atm

(conversion used : 1 atm = 760 mmHg)

V = volume of gas = 1 L

T = temperature of gas = 373 K

$n_{O_2}$ = number of moles of oxygen gas = ?

$n_{CO_2}$ = number of moles of carbon dioxide gas = 0.025 mole

R = gas constant = $0.0821L.atmK^{-1}mol^{-1}$

Now put all the given values in the ideal gas equation, we get:

$(0.8atm)\times (1L)=(n_{O_2}+0.025)mole\times (0.0821L.atmK^{-1}mol^{-1})\times (373K)$

$n_{O_2}=0.001124mole$

Now we have to calculate the mass of oxygen gas.

$\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2$

$\text{Mass of }O_2=0.001124mole\times 32g/mole=0.03597g$

Therefore, the mass of oxygen present in the flask is 0.03597 grams.

7 0

4 years ago

How did the atomic theory develop

olasank [31]

It was the English chemist, John Dalton, who put the pieces of the puzzle together and developed an atomic theory in 1803. Dalton 's atomic theory<span> contains five basic assumptions:

- All matter consists of tiny particles called </span>atoms<span>.
</span>- Atoms are indestructible and unchangeable.- Elements are characterized by the weight of their atoms.
- In chemical reactions, atoms combine in small, whole-number ratios.
- When elements react, their atoms may combine in more than one whole-number ratio.

Hope this helped!

4 0

3 years ago

How many molecules are there in 2 moles of FeF3

Pie

Answer:it is 4

Explanation:

I multiple and divided it

4 0

3 years ago

Which statement is most likely correct about two rocks belonging to the same age, one containing fossils of an amphibian and the

alexira [117]

The correct answer is option B. The amphibian and mosses belonged to the same age.

Since the rocks belong to the same age and one contain fossils of an amphibian and the other containing fossils of mosses, it is very likely that both the amphibian and the mosses existed at the same time.

Sedimentary rocks generally have fossils in them and it is very easy to determine the age of the fossils from Radiometric Dating using radioactive carbon C¹⁴. However, before the complete understanding of radioactive decay fossil, age was determined by studying the succession of fossils on old to younger sedimentary rocks.

4 0

3 years ago

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The structure of EDTA​

The structure of EDTA