Answer:
5.92 g
Explanation:
Convert milliliters to liters.
217 mL = 0.217 L
Since molarity (M) is moles per liter(mol/L), multiply the molarity by the volume to find out how many moles you will need.
0.217 L × 0.246 M = 0.05338 mol
Now, convert the moles to grams using the molar mass. The molar mass of calcium chloride is 110.98 g/mol.
0.05338 mol × 110.98 g/mol = 5.924 g ≈ 5.92 g
You will need 5.92 g of calcium chloride.
This might get a little salt out but you will need to evaporate the water to completely get the salt out. Once you evaporate the water all that will be left is the salt
1 mol of CO2 is 44.01g/mol
So multiply that by 2 to get 2 mol of CO2, which is 88.02g
Answer: 48,501 J/mol
Explanation:
1) Action barrier = activation energy = Ea
2) Data:
i) T₁ = 12°C = 12 + 273.15 K = 285.15K
ii) T₂ = 22°C = 22 + 273.15 K = 295.15 K
iii) rate constant = k: k₂ / k₁ = 2
iv) Ea = ?
3) Formula:
Arrhenius' law gives the relationship between the constant of reaction and the temperature:
4) Solution
By arranging the formula, you get:
㏑[k₂/k₁] =Ea/R [1/T₁ - 1/T₂]
Replace k₂ = 2k₁; T₁ = 285.15; and T₂ = 295.15
ln[2] = Ea/8.314 J/K mol × [1/285.15 - 1/295.15]K
Ea = ln [2] × 8.314 J/K mol / [1.18818×10⁻⁴K] = 48,501 J/mol
Answer:
HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)
H⁺(aq) + OH⁻ ⇒ H₂O(l)
Explanation:
Let's consider the balanced chemical equation (molecular equation) for the reaction between hydrochloric acid and sodium hydroxide. This is a neutralization reaction.
HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)
The complete ionic equation includes all the ions and the molecular species.
H⁺(aq) + Cl⁻(aq) + Na⁺(aq) + OH⁻ ⇒ Na⁺(aq) + Cl⁻(aq) + H₂O(l)
The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the molecular species.
H⁺(aq) + OH⁻ ⇒ H₂O(l)