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Andrej [43]
2 years ago
14

What percent of 32 is 10

Mathematics
2 answers:
Vinvika [58]2 years ago
8 0

Answer:

31.25%

Step-by-step explanation:

We can write this as a fraction:

10/32

Now you divide it to get a decimal:

10 ÷ 32 = 0.3125

0.3125 = 31.25%

Hope this helps!

Dennis_Churaev [7]2 years ago
7 0

Answer:

31.25

Step-by-step explanation:

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Find area of a rectangle that measures 18yd by 14yd
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32.

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The probability of it snowing in Eastern Canada tomorrow is 0.4. The probability of it snowing in Western Canada tomorrow is 2/5
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Neither

Step-by-step explanation:

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3 years ago
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
2 years ago
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