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Andrej [43]
3 years ago
14

What percent of 32 is 10

Mathematics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

31.25%

Step-by-step explanation:

We can write this as a fraction:

10/32

Now you divide it to get a decimal:

10 ÷ 32 = 0.3125

0.3125 = 31.25%

Hope this helps!

Dennis_Churaev [7]3 years ago
7 0

Answer:

31.25

Step-by-step explanation:

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Rewrite as a simplified faction
elena-s [515]
Here is the final answer
3 2/9
=29/9. Hope it help!
8 0
3 years ago
If two angles of a triangle each measure 45 degrees what is the third angle
8_murik_8 [283]

Since we know that there are exactly 180 degrees in any triangle, and if each angle is equal to 45 degrees, we must add 45 to 45 and then subtract the result from 180 to find the 3rd angle. Since 45+45=90,we subtract 180-90 and get 90 degrees or a right angle.


5 0
3 years ago
Read 2 more answers
Brand A has a recognition value worth ​$47 billion more than brand B. If the total value of these two brands is ​$101 ​billion,
gladu [14]
A+B=$101 billion
A=B+$47 billion

2B+$47 billion=$101 billion.
2B=$54 billion
B=$27 billion

A=B+$47 billion
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3 0
3 years ago
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
3 years ago
Estimate the mean number of games the boys attended.
Olin [163]

Answer:

the mean is 8

Step-by-step explanation:

5 +7+8+8+9+11= 48  

48/6= 8

6 0
3 years ago
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