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3 years ago

A coin is flipped 150 times. The results of the experiment are shown in the following table:

Mathematics

1 answer:

MakcuM [25]3 years ago

7 0

First problem:

The answer is C because theoretically it should have a 50% of landing heads but instead it lands heads 56% of the time. Thus this is 6% higher than 50%. It's not D because there is not specified detail of how the person got this data so you can assume that the person did a fair survey/data collection.

Second problem:

So in a data size of 490, 140 of them we trout. This means that 140/490 or 28.57% of the fish are trout. This means that in a sample size of 5000 fish, 5000*0.2857 or 1428.57 are trout.

Third problem:

The Science students seem to have a higher average score because the average score of Math students are:
(32+33+34+34+35+37+39+40+40)/9=36
average score of Science students are:
(41+42+43+43+46+46+47+49+49)/9=45.111

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Given that F(x) = x 2 + 2, evaluate F(1) + F(5) <br> which is the answer? 38 30 15

Valentin [98]

your answer is 30

1^2 (raised to the power of 2) +2 is 3

5^2 +2 is 27

5^2=25

1^2=1

add 27+3=30

6 0

3 years ago

2c + 1 = -31.......................................

maksim [4K]

Answer:

c = -16

Step-by-step explanation:

2c = -32

c = -16

3 0

3 years ago

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A city has 5 new houses for every 9 old houses. If there are 35 new houses in the city, how many old houses are there?

Nezavi [6.7K]

Answer:

C.) 63

Step-by-step explanation:

You know what you insisted on me answering, so I'll answer here.

35 ÷ 5 = 7

7 x 9 = 63

7 0

3 years ago

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A card is picked from a standard deck of 52 cards. Determine the odds against and the odds in favor of selecting a red face card

timama [110]

<h3>The probability of picking a red face card from the deck is $(\frac{3}{26} )$ </h3><h3>The probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$ </h3>

Step-by-step explanation:

The total number of cards in the deck = 52

The total number of red( Diamond + Hearts) face cards in the given deck

= 2 Red Queens + 2 Red jacks + 2 Red kings = 6 cards

Let E : Event of picking a red face card from the deck

Now , P( any event) = $\frac{\textrm{The number of favorable observations}}{\textrm{Total number of observations}}$

So, here P(Picking a red face card) = $\frac{\textrm{The number of red face cards}}{\textrm{Total number of cards}} = (\frac{6}{52} ) = (\frac{3}{26})$

Hence, the probability of picking a red face card from the deck is $(\frac{3}{26} )$

Now, as we know P (any event NOT A) = 1 - P(any event A)

So, P(NOT Picking a red face card) = 1 - P(Picking a red face card)

$= 1 - (\frac{3}{26} ) = \frac{26-3}{26} = (\frac{23}{26})$

Hence, the probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$

8 0

3 years ago

Find the right quotient. 36m 5 n 5 ÷ (12m 3)

polet [3.4K]

ANSWER

The right quotient is

$3 {m}^{2} {n}^{5}$

EXPLANATION

The given expression is :

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} }$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = \frac{36}{12} \times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3\times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

Recall that,

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$
We apply this property to obtain;

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 \times {m}^{5 - 3} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 {m}^{2} {n}^{5}$

5 0

3 years ago

Read 2 more answers