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3 years ago

. The method of spreading the seeds manually in the leveled ground for crops to grow is called

Chemistry

1 answer:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

The process of sowing seeds manually called broadcasting or manual sowing. Broadcasting is a method of sowing by scattering seeds all over the prepared soil surface. Crop seeds like wheat, paddy, methi, coriander etc. are sawn in this method.

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Which is the correctly balanced equation?

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A) Cl2 + 2NaI = 2NaCl + I2

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Which of the following is an example of an atom "following" the octet rule?

lukranit [14]

B) A nitrogen atom that has 5 valence electrons gains 3 more electrons to become a nitride (N3-)

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4 years ago

what is the percent yield of titanium (II) oxide if 20.0 grams of titanium (II) sulfide is reacted with water? The actual yield

earnstyle [38]

Answer : The percent yield of titanium (II) oxide is, 142.5 % and the impurities could have caused the percent yield to be so high.

Explanation : Given,

Mass of titanium(II) sulfide = 20.0 g

Molar mass of titanium(II) sulfide = 79.9 g/mole

Molar mass of titanium(II) oxide = 63.9 g/mole

First we have to calculate the moles of titanium(II) sulfide.

$\text{ Moles of titanium(II) sulfide}=\frac{\text{ Mass of titanium(II) sulfide}}{\text{ Molar mass of titanium(II) sulfide}}=\frac{20.0g}{79.9g/mole}=0.2503moles$

Now we have to calculate the moles of titanium(II) oxide.

The balanced chemical reaction is,

$TiS+H_2O\rightarrow TiO+H_2S$

From the reaction, we conclude that

As, 1 mole of titanium(II) sulfide react to give 1 mole of titanium(II) oxide

So, 0.2503 mole of titanium(II) sulfide react to give 0.2503 mole of titanium(II) oxide

Now we have to calculate the mass of titanium(II) oxide.

$\text{ Mass of titanium(II) oxide}=\text{ Moles of titanium(II) oxide}\times \text{ Molar mass of titanium(II) oxide}$

$\text{ Mass of titanium(II) oxide}=(0.2503moles)\times (63.9g/mole)=15.99g$

To calculate the percentage yield of titanium (II) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of titanium (II) oxide = 22.8 g

Theoretical yield of titanium (II) oxide = 15.99 g

Putting values in above equation, we get:

$\%\text{ yield of titanium (II) oxide}=\frac{22.8g}{15.99g}\times 100\\\\\% \text{yield of titanium (II) oxide}=142.5\%$

Hence, the percent yield of titanium (II) oxide is, 142.5 %

If the percent yields is greater than 100% that means the product of the reaction contains impurities which cause its mass to be greater than it actually.

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3 years ago

Ill mark brainliness just please help :( science suck

vivado [14]

I really don’t know but I’d guess city s

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3 years ago

Why must the mass of magnesium be less than 0.09 g?

SVEN [57.7K]

The mass of magnesium should be less than 0.09g to enable a faster reaction rate. Magnesium reacts to form a white coating around it which stops the reaction. The lesser the gram the faster the reaction before the coating is formed. It is also advisable to use magnesium fillings to increase the rate of reaction.

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3 years ago

. The method of spreading the seeds manually in the leveled ground for crops to grow is called​

. The method of spreading the seeds manually in the leveled ground for crops to grow is called