Atomic radius- a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding cloud of electrons.
Electron Affinity-the electron affinityof an atom or molecule is defined as the amount of energy released or spent when an electron is added to a neutral atom or molecule in the gaseous state to form a negative ion.
Electronegativity-a measure of the tendency of an atom to attract a bonding pair of electrons. The Pauling scale is the most commonly used. Fluorine (the most electronegative element) is assigned a value of 4.0, and values range down to caesium and francium which are the least electronegative at 0.7.
Lonization energy- qualitatively defined as the amount of energy required to remove the most loosely bound electron, the valence electron, of an isolated gaseous atom to form a cation.
Answer:
hey there
<u>Density;</u>
The amount of mass or particles per unit of space.
for example, the density of water is 997 kg/m³
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<u>Volume;</u>
the amount of space something takes up.
For example Mars is 163 billion cubic kilometers^3
To find the third side you would use Pythagorean theorem which is a²+b²=c².
A and B being the 2 legs and C being the hypotenuse.
Example: ( sorry for the really odd not really a triangle, triangle...)
| \
6| \ ? 6²+9²=C²
|_______ 36+81=C²
9 117=C²
√117=10.8 (rounded)
if you need to get the leg you just fill in the numbers.
The differential change in entropy of a system is
given as: <span>
<span>dS = (∂S/∂T)_V dT </span>
We also know that </span>
<span>(∂S/∂T)_V = n*Cv/T, </span>
Where Cv is the molar heat capacity at constant
volume, and n is the number of moles. Combining the 2 equations:<span>
dS = n*Cv/T dT
Since Cv is constant as stated in the problem, therefore we
integrate the differential equation. Leading us to:
ΔS = n*Cv*ln(Tfinal/Tinitial)
<span>We are given that: V =
18L volume at P=2 kPa and T=298.15K. </span></span>
Using the ideal gas law to find the number of
moles of gas: <span>
n = p*V/R*T = (2kPa)*(18L)/((298.15K)*(8.314 L*kPa/(mol*K)))
n = 1.45*10^-2 mol
Going back to the entropy change:
ΔS = (1.45*10^-2 mol)*(20.17 J/(K*mol))*ln(1073.15/298.15)
<span>
<span>ΔS = 0.375 J/K</span></span></span>
The answer is A.
We know the formula for molarity :
<u>Molarity = Number of moles ÷ Volume</u>
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Let's assume there are 0.6 moles of NaCl in 1 liter of ocean water.
Then, mass of salt is :
- Mass of one mole salt × 0.6
- 58.5 × 0.6
- 35 grams
