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Alex787 [66]
3 years ago
9

Solve the system: {4x-7y=30, 4x-5y=90

Mathematics
1 answer:
Lerok [7]3 years ago
7 0

Answer:

x=60, y=30

Step-by-step explanation:

4x-7y=30

4x-5y=90

Subtract the equations

4x-7y=30-4x-5y=90

=2y=60

Solve 2y=60

Divide both sides by 2

2y/2=60/2

Simplify;

y=30

For 4x-7*30=30 for x

4x-7y*30=30

Multiply the numbers:7*30=210

4x-210=30

Add 210 to both sides

4x-210+210=30+210

Simplify;

4x=240

Divide both sides by 4

4x/4=240/4

Simplify

x=60

The solutions to the system of equations are:

x=60, y=30

Hope this helped!!!

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I will give BRAINLIEST to the correct answer <br> Find the measure of
Damm [24]

Answer: SOLN,

let,<FHC be x

<GHC+<FHC( sum of  angle of triangle=180 degree

 x+6m+55+8m+55=180

 x+ 14m+110=180

  x+14m=180-110

  x+14m=70

    x=70 divied by 14m  

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therefore,the value of <FHC is 5m.      

6 0
3 years ago
I have to find the area of this rectangular prism pls help!!
Nina [5.8K]

Answer:

the surface area is 208

Step-by-step explanation:

formula for surface area is A = 2 (w*l + h*l + h*w )

A = 2 ( 4*8 + 6*8 + 6*4 )

A = 2 ( 32 + 48 + 24 )

A = 2 ( 104 )

A = 208

8 0
2 years ago
F(m)=m^4-6m^3+5m^2+10m-4 at m=4
Alexandra [31]

Answer:

F(m) = -12

Step-by-step explanation:

Given the function:

F(m)=m^{4}-6m^{3}+5m^{2}+10m-4

When m = 4, we substitute the variable 'm' for the number 4:

F(m)=4^{4}-6(4)^{3}+5(4)^{2}+10(4)-4

F(m) = 256 - 384 + 80 + 40 - 4

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6 0
3 years ago
Can a polynomial have a zero as a term
Mnenie [13.5K]

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No

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7 0
3 years ago
The focus of a parabola is (0, -3) and the directrix is y = 3. What is the equation of the parabola?
OleMash [197]

Answer:

The equation of the parabola is y = -12\cdot x^{2}.

Step-by-step explanation:

Since the directrix is of the form y = a, the parabola is vertical. The vertex of the parabola (V(x,y)) is the midpoint between the focus (F(x,y)) and a point of the directrix (P(x,y)), that is to say:

V(x,y) = \frac{1}{2}\cdot F(x,y) + \frac{1}{2}\cdot P(x,y) (1)

If we know that F(x,y) = (0, -3) and P(x,y) = (0, 3), then the coordinates of the vertex of the parabola:

V(x,y) = \frac{1}{2}\cdot (0, -3) + \frac{1}{2}\cdot (0, 3)

V(x,y) = (0, 0)

The vertex factor (p) is the distance of the focus with respect to the vertex:

p = \sqrt{[F(x,y)-V(x,y)]\,\bullet \,[F(x,y)-V(x,y)]} (2)

If we know that F(x,y) = (0, -3) and V(x,y) = (0, 0), then the vertex factor is:

p = \sqrt{0^{2}+(-3)^{2}}

p = -3

The equation of the parabola in the vertex form is described below:

y - k = 4\cdot p \cdot (x-h)^{2} (3)

Where:

x - Independent variable.

y - Dependent variable.

h, k - Coordinates of the vertex.

If we know that (h,k) = (0, 0) and p = -3, then the equation of the parabola is y = -12\cdot x^{2}.

6 0
2 years ago
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