The value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
<h3>What is the rate of speed?</h3>
The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,
r=d/t
Here, (d) is the distance travelled by the object and (t) is time taken but the object to cover that distance.
The train traveled 1/3 of the distance at 30 mph and the remaining distance at 40 mph. Let <em>t</em> is the time the train has taken to travel and x is the distance it travelled. Thus,
After two hour a car left the same station traveled the first 3 hours at 35 mph and the remaining distance at 51 mph. Let <em>t</em> is the time the car has taken to travel and x is the distance it travelled. Thus,
As t is same, thus put the value of t in this equation,
Thus, the value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
Learn more about the rate of speed here:
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−1/3⋅(8 1/7)
change 8 1/7 to an improper fraction
8 1/7 = (7*8 +1)/7 = 57/7
-1/3 * 57/7
-57/21
21 goes into 57 2 times with 15 left over
-2 15/21
divide top and bottom of the fraction by 3
-2 5/7
Choice B
-6*3 =-18
11*4=44
-18/44. Reduce. Divide top and bottom by 2
-9/22
B. It would be 5/2 and -3/4.
Answer:
Hotdog: $3.00
Hamburger: $4.00
Step-by-step explanation:
For the first time that Bob buys food, we can make an equation to find how much a single hotdog and a single hamburger costs, where:
x = cost of a hotdog
y = cost of a hamburger
He bought 2 hotdogs and 1 hamburger for $10, so the equation for his first time buying food is:
2x + y = 10
For the second time buying food, he bought 1 hotdog and 3 hamburgers for $15, so his equation would be:
x + 3y = 15
To find the value for x and y we need to solve this system of equations using the two equations we just came up with. We can do this multiple ways, but I'll be demonstrating the substitution method.
Using the second equation, we can solve for x by simply subtracting 3y from both sides:
x = 15 - 3y
We can then insert this value of x into the first equation so that way we are only dealing with one variable to solve - y:
2(15-3y) + y = 10
Distribute out the 2 into the paratheses, combine like terms, and then solve for y:
30 - 6y + y = 10
30 - 5y = 10
-5y = -20
y = 4
This means the cost for one hamburger is $4. But we still need to find the price of one hotdog, so we can insert this value of y into the equation we came up with earlier for x, and then solve for x:
x = 15 - 3y
x = 15 - 3(4)
x = 15 - 12
x = 3
So the price of one hotdog is $3 and the price of one hamburger is $4. Hope this helps.
