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HACTEHA [7]
3 years ago
12

Draw the Lewis dot diagrams for F2, N2, and C2. Compare your drawing to the ones below. Which of the below Lewis dot diagram or

diagrams is/are wrong and why?

Chemistry
1 answer:
torisob [31]3 years ago
6 0

answer: i believe it is N2 is wrong because it has a double bond

Explanation:

i need help as well

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Why are properties of covalent compounds so diverse
faltersainse [42]

Answer:

The diversity of physical properties among covalent compounds is mainly because of widely varying intermolecular attractions. ... All of the atoms are covalently bonded to each other.

5 0
2 years ago
Does any one have a sixth grade Ohio science fusion book
eimsori [14]
Nope, sure don't sesrch it on amazon or something. Maybe youll find one and be able to but it.
6 0
3 years ago
Aluminum metal and manganese (IV) oxide react to produce aluminum oxide and manganese metal. What mass of manganese (IV) oxide r
gayaneshka [121]

Answer: 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

Explanation:

The balanced chemical equation is:

4Al+3MnO_2\rightarrow 2Al_2O_3+3Mn

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of manganese = \frac{1.12\times 1000g}{55g/mol}=20.4mol

According to stoichiometry :

3 moles of Mn is produced by = 3 moles of MnO_2

Thus 20.4 moles of Mn is produced by =\frac{3}{3}\times 20.4=20.4moles  of MnO_2

Mass of MnO_2=moles\times {\text {Molar mass}}=20.4moles\times 86.9g/mol=1773g=1.773kg    (1kg=1000g)

Thus 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

6 0
3 years ago
How do you balance redox equations in acidic solutions?
Anuta_ua [19.1K]

Answer:

First, balance the half-reactions

Second, equalize the electrons

Third,add two reaction equations to get final answer

Explanation:

For example

H₂C₂0₄ + MnO⁻₄ ---------->CO₂+Mn²⁺

(i) Balancing the half reactions

H₂C₂O₄-------->2CO₂+2H⁺+2e⁻

5e⁻ +8H⁺+MnO₄⁻----------->Mn²⁺+4H₂O

(ii)

Equalizing the electrons

5H₂C₂O₄--------->10CO₂+10H⁺+10e⁻  ---here there is a factor of 5

10e⁻+16H⁺+2MnO₄⁻--------->2Mn²⁺+8H₂O -----here there is a factor of 2

(iii)

Add the two where electrons and some Hydrogen ions will cancel out

5H₂C₂O₄+6H⁺+2MnO₄⁻---->10CO₂+2Mn²⁺+8H₂O

7 0
2 years ago
Identify each of the following compounds as binary or ternary. Then write the chemical formula for each ionic compound.
Maurinko [17]
Binary compounds have 2 different elements, and ternary compounds have 3
Nickel(III)oxide:  binary, Ni2O3
Copper (II)iodide: binary, CuI2
Tin(IV) nitride: binary, Sn3N4
Chromium (II)bromide: binary, CrBr2
<span>Iron(III)phosphide: binary, FeP</span>
7 0
3 years ago
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