Answer:
40.03g/mole
Explanation:
Given parameters:
Mass = 42.10 g/mole and abundance = 93.50%
Mass = 8.30 g/mole and abundance = 6.200%
Mass = 50.40 g/mole and abundace = 0.3000%
Find;
Average atomic mass = ?
Solution:
Average atomic mass = sum (mass x abundance)
Average atomic mass = () + (
x 8.3) + (
)
= 39.36g/mole + 0.52g/mole + 0.15g/mole
= 40.03g/mole
Answer:
Potential energy
Explanation:
Answer : The equilibrium concentration of NO is, 0.0092 M.
Solution :
First we have to calculate the concentration of NO.
The given equilibrium reaction is,
Initially conc. 0 0 0.1576
At eqm. (x) (x) (0.1576-2x)
The expression of will be,
By solving the term, we get:
Neglecting the 0.0839 value of x because it can not be more than initial value.
Thus, the value of 'x' will be, 0.0742 M
Now we have to calculate the equilibrium concentration of NO.
Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M
Therefore, the equilibrium concentration of NO is, 0.0092 M.