The major product is p-bromo N,N,N -trimethylaniliniumiodide when p-bromoaniline react with excess CH₃I.
<h3>
What is Alkylation of p-bromoaniline ?</h3>
When p-bromoaniline react with methyl iodide it produces p-bromo N,N-dimethylaniline.
<h3>What happens when p-bromo N,N-dimethylaniline. reacts with excess methyl iodide ? </h3>
When p-bromo N,N-dimethylaniline reacts with excess methyl iodide leading to the production of p-bromo N,N,N -trimethylaniliniumiodide.
Thus from the above conclusion we can say that The major product is p-bromo N,N,N -trimethylaniliniumiodide. when p-bromoaniline react with excess CH₃I.
Learn more about the Alkylation here: brainly.com/question/27927775
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<u>Answer:</u> For the given reaction, the value of is greater than 1
<u>Explanation:</u>
For the given chemical equation:
The expression of for above equation follows:
The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression
As, the denominator is missing and the numerator is the only part left in the expression. So, the value of will be greater than 1.
Hence, for the given reaction, the value of is greater than 1
This is a synthesis reaction or a combination reaction
Answer:
The atomic mass of element X is 69.724 amu
Explanation:
Given data:
Atomic mass of element X= ?
Percent abundance of X-68.926 = 60.10%
percent abundance of X-70.925 = 39.90%
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (68.926×60.10)+(70.925×39.90) /100
Average atomic mass = 4142.4526 +2829.9075/ 100
Average atomic mass = 6972.3601 / 100
Average atomic mass = 69.724 amu.
The atomic mass of element X is 69.724 amu.