The particle that adds mass but no charge to the atomic nucleus is the neutron.
The nucleus contains both protons and neutrons.
Protons and neutrons have about the same mass.
However, protons have a positive charge, while <em>neutrons have no charge</em>,
Hello Lilsavage717, I believe the answer you are looking for is C. or Amino Acids. They are mainly located in living things like plants or bugs.
Explanation:
The chemical reaction equation will be as follows.

As 1 mole
reacts with 1 mole of
Hence, moles of
= Molarity × Volume (in mL)
= 0.5 × 38.0 mL
= 0.019 mol
Moles of
= Molarity × Volume (in mL)
= 0.6 × 42.0 mL
= 0.0252 mol
As moles of CuS is less than the moles of
. This means that CuS is the limiting reagent.
Thus, maximum moles of CuS formed are 0.019 mol. As molar mass of CuS is 95.6 g/mol.
Therefore, maximum mass of CuS can be formed is 
= 1.8164 g
Thus, we can conclude that maximum mass of CuS formed is 1.8164 g.
Answer:
The rate law for second order unimolecular irreversible reaction is
![\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%20k.t%20%2B%20%5Cfrac%7B1%7D%7B%5BA%5D_%7B0%7D%20%7D)
Explanation:
A second order unimolecular irreversible reaction is
2A → B
Thus the rate of the reaction is
![v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}](https://tex.z-dn.net/?f=v%20%3D%20-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D%20%3D%20k.%5BA%5D%5E%7B2%7D)
rearranging the ecuation
![-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bk%7D%7Bdt%7D%20%3D%20%5Cfrac%7B%5BA%5D%5E%7B2%7D%7D%7Bd%5BA%5D%7D)
Integrating between times 0 to <em>t </em>and between the concentrations of
to <em>[A].</em>
![\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_t%20-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bk%7D%7Bdt%7D%20%3D%5Cint%5Climits%5EA_%7B0%7D%20_A%5Cfrac%7B%5BA%5D%5E%7B2%7D%7D%7Bd%5BA%5D%7D)
Solving the integral
![\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%20k.t%20%2B%20%5Cfrac%7B1%7D%7B%5BA%5D_%7B0%7D%20%7D)
Explanation:
When we find elements with high ionization energy in the upper right corner because the zeff experienced by the outer electron is high and electrons that are close to the nucleus.
The low Ionization energy elements are found in lower left where majority is of metals. The Zeff is low as the outer electrons are distance from the nucleus.