Answer :
B
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Because the valence shell of gases wants to become full
Answer:
a. Methanol remains the same
b. Methanol decreases
c. Methanol increases
d. Methanol remains the same
e. Methanol increases
Explanation:
Methanol is produced by the reaction of carbon monoxide and hydrogen in the presence of a catalyst as follows; 2H2+CO→CH3OH.
a) The presence or absence of a catalyst makes no difference on the equilibrium position of the system hence the methanol remains constant.
b) The amount of methanol decreases because the equilibrium position shifts towards the left and more reactants are formed since the reaction is exothermic.
c) If the volume is decreased, there will be more methanol in the system because the equilibrium position will shift towards the right hand side.
d) Addition of helium gas has no effect on the equilibrium position since it does not participate in the reaction system.
e) if more CO is added the amount of methanol increases since the equilibrium position will shift towards the right hand side.
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You have OH- conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3
So, for 2.3 ✕ 10−6 m OH-
[Cu2+] =
Answer:
Option C. 13.5 atm
Explanation:
From the question given above, the following data were obtained:
Pressure of Neon (Pₙₑ) = 4.1 atm
Pressure of Argon (Pₐᵣ) = 3.2 atm
Pressure of nitrogen (Pₙ₂) = 6.2 atm
Total pressure (Pₜ) =?
The total pressure in the container can be obtained by adding the pressure of the individual gases. This is illustrated below:
Pₜ = Pₙₑ + Pₐᵣ + Pₙ₂
Pₜ = 4.1 + 3.2 + 6.2
Pₜ = 13.5 atm
Therefore, the total pressure in the container is 13.5 atm
