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gtnhenbr [62]
3 years ago
12

Molar mass of Fe(NO3)3

Chemistry
1 answer:
polet [3.4K]3 years ago
6 0
Answer: 241. 8g. Add the mass of Fe, 3 N masses (because of the 3 outside the parenthesis), and add the 9 O because of the 3 next to it and the 3 outside. This results to 55.846+42.0201+143.946g that equals 241.8g. I hope this helps
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<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

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Putting values in above equation, we get:

0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol

For the given chemical reaction:

BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = \frac{1}{1}\times 0.00286mol=0.00286mol of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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Putting values in above equation, we get:

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