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3 years ago

7

If we have a sample of silicon (Si) atoms that has 14 protons, 14 electrons, and 18 neutrons

1 answer:

Pie3 years ago

8 0

The name of this specific silicon isotope is Si -18

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What are the similarities and differences between light microscopes used by early scientists and light microscopes used today?

Aleks [24]

Electron microscopes differ from light microscopes in that they produce an image of a specimen by using a beam of electrons rather than a beam of light. Electrons have much a shorter wavelength than visible light, and this allows electron microscopes to produce higher-resolution images than standard light microscopes

3 0

2 years ago

Definition of volume

AysviL [449]

Answer:

The amount of space an object occupies.

Explanation:

3 0

3 years ago

If the volume of a gas at 0.5 atm changes from 150 mL to 75 mL, what is the new pressure?

prisoha [69]

Answer:

<h2>1 atm</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we're finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

We have

$P_2 = \frac{0.5 \times 150}{75} = \frac{75}{75} = 1 \\$

We have the final answer as

<h3>1 atm</h3>

Hope this helps you

5 0

3 years ago

g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint

diamong [38]

Answer:

The value is $L = 0.985 \pm 0.00801 \ g$

Explanation:

From the question we are told that

The molar mass of $CaCO_3$ is $MW = 100.085 \ g/mol$

The total mass is $m_g = 12.3 \ g$

The uncertainty of the total mass is $\Delta g = 0.1$

Generally the molar weight of calcium is $M_c = 40 g/mol$

The percentage of calcium in calcite is mathematically represented as

$C = \frac{40.07}{100.085} * 100$

$C = 40.03 \%$

Generally the mass of each sample is mathematically represented as

$m= \frac{m_g}{5}$

$m= \frac{12.3}{5}$

$m= 2.46 \ g$

Generally mass of calcium present in a single sample is mathematically represented as

$m_c = 2.46 * \frac{40.04}{100}$

$m_c = 0.985 \ g$

The uncertainty of mass of a single sample is mathematically represented as

$k = \frac{\Delta g }{5}$

$k = \frac{0.1 }{5}$

$k = 0.02\ g$

The uncertainty of mass of calcium in a single sample is mathematically represent

$G = \frac{0.02 * 40.04}{ 100}$

$G = 0.00801 \ g$

Generally the average mass of calcium in each sample is

$L = 0.985 \pm 0.00801$

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2 years ago

What atoms are in Au(NO2)2

Fiesta28 [93]

Au, N, O ( give me brainliest please)

4 0

2 years ago