In the reaction of water, 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.
<h3>What is reducing agent?</h3>
A reducing agent is a type of chemical that "donates" an electron to another atom that needs an electron. This type of reaction in which loss of electron occurs is called reduction reaction.
So we can conclude that 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.
Learn more about reduction here: brainly.com/question/3457976
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Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent composition of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
This is the answer to question 19. If it’s not clear, send me a message.
The answer is Na < Cl
Chlorine is more electronegative than sodium because this follows the trend of the periodic table. The trend states that an element's electronegativity increases from left to right of a period and bottom to up of a group. Since sodium and chlorine are from the same period, and chlorine is at the right of sodium, chlorine is more electronegative.
According to the chemical equation, the ratio between Ca and HCl for a complete reaction is 1:2. The moles of Ca can be calculated by mass/molar mass, thus 60.0 g/40 g/mole = 1.5 mole. So the moles of HCl in the solution is 1.5mole*2 = 3 mole.
So the volume of HCl solution = Moles of HCl/ concentration of HCl = 3 mole/ 1.25 M = 2.4 L = 2400 mL
