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gayaneshka [121]
3 years ago
9

5. Which type of substance yields hydrogen ions, H+, in

Chemistry
1 answer:
GaryK [48]3 years ago
7 0

Answer: An Arrhenius acid is a type of substance yields hydrogen ions, H^{+}, in an aqueous solution.

Explanation:

Substances that give dissociate to give hydrogen ions or protons when dissolved in an aqueous solution are called Arrhenius acid.

For example, HCl is a strong acid and upon dissociation in water it gives the following ions.

HCl \rightarrow H^{+} + Cl^{-}

Thus, we can conclude that an Arrhenius acid is a type of substance yields hydrogen ions, H^{+}, in an aqueous solution.

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What is the relationship between the number of each atom used to form compound and oxidation number?
deff fn [24]

Answer:Explanation:

In compounds, all other atoms are assigned an oxidation number so that the sum of the oxidation numbers on all the atoms in the species equals the charge on the species.

6 0
3 years ago
Why are the average atomic masses of some of the elements in parentheses?
Pie
Because its only representing the most stable isotope of that element but its considered the atomic mass and not average atomic mass
4 0
3 years ago
12. Which atoms or group of atoms make up the functional group of ethanol (CH3CH2OH)?
Montano1993 [528]

Answer:

Option A. the hydroxyl group (-OH)

Explanation:

Ethanol, CH₃CH₂OH belongs to the class of organic compound called alkanol.

They have general formula as R–OH

Where

R => is an alkyl group

OH => is the hydroxyl group

The hydroxyl group (OH) is the functional group of the alkanol (alcohol)

8 0
2 years ago
Calculate the molarity of the solution formed when 0.72 moles of CaBr2 is dissolved in 1.50 L water.
xxTIMURxx [149]

Answer:

The molarity of the formed CaBr2 solution is 0.48 M

Explanation:

Step 1: Data given

Number of moles CaBr2 = 0.72 moles

Volume of water = 1.50 L

Step 2: Calculate the molarity of the solution

Molarity of CaBr2 solution = moles CaBr2 / volume water

Molarity of CaBr2 solution = 0.72 moles / 1.50 L

Molarity of CaBr2 solution = 0.48 mol / = 0.48 M

The molarity of the formed CaBr2 solution is 0.48 M

4 0
3 years ago
A 1.0 g sample of propane, C3H8, was burned in calorimeter. The temperature rose from 28.5 0C to 32.0 0C and heat of combustion
tensa zangetsu [6.8K]

Answer:

A 1.0 g sample of propane, C3H8, was burned in the calorimeter.

The temperature rose from 28.5 0C to 32.0 0C and the heat of combustion 10.5 kJ/g.

Calculate the heat capacity of the calorimeter apparatus in kJ/0C

Explanation:

Heat of combustion = heat capacity of calorimeter * deltaT\\

Given,

The heat of combustion = 10.5kJ/g.

deltaT = (32.0-28.5)^oC\\deltaT = 3.5^oC

Substitute these values in the above formula to get the value of heat capacity of the calorimeter.

deltaT =heat  capacity of calorimeter   * (change in temperature)\\10.5kJ/g = heat  capacity of calorimeter * (3.5^oC)\\\\=>heat capacity of calorimeter = \frac{10.5kJ/g}{3.5^oC} \\=>heat capacity of calorimeter = 3.0 kJ/g.^oC

Answer:

The heat capacity of the calorimeter is 3.0kJ/g.^oC.

5 0
3 years ago
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