Waves travel through matter, so I am 99.9% sure that is the answer.
Id look through your lesson to be sure!
Answer:
1-Pentene
Explanation:
If we look at all the options listed, we will notice that the rate of reaction of bromine with each one differs significantly.
For 1-pentene, addition of bromine across the double bond is a relatively fast process. It is usually used as a test for unsaturation. Bromine water is easily decolorized by alkenes.
Cyclohexane, heptane are alkanes. They can only react with chlorine in the presence of sunlight. This is a substitution reaction. It does not occur easily. A certain quantum of light is required for the reaction to occur.
For benzene, bromine can only react with it by electrophilic substitution in which the benzene ring is retained. A Lewis acid is often required for the reaction to occur and it doesn't occur easily.
Answer:
2 hours Speed =110/2=55 miles ler hour
The term "valence electrons" refers to all of the electrons in an atom's outermost shell.
The centre of the atom is where the nucleus is. The nucleus contains protons and neutrons. The electrons travel in a specific circular direction and at a specific distance from the nucleus.
The atom's final shell's electrons take part in chemical reactions and the production of bonds. Both ionic and covalent bonding involve valence electrons. Metals are elements with one, two, or three electrons in their final shell.
These substances become positive ions after losing their electrons. Non-metals are substances with 5, 6, or 7 electrons in the outermost shell. These substances all gain electrons and change into negative ions.
Ionic bonds are those created by the transfer of electrons between metals and non-metals. For instance, ionic bonding allows sodium and chlorine to interact to generate sodium chloride.
To know more about valence electrons here
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Answer:
See Explanation
Explanation:
Let us consider the first two reactions, the initial concentration of CO was held constant and the concentration of Hbn was doubled.
2.68 * 10^-3/1.34 * 10^-3 = 6.24 * 10^-4/3.12 * 10^-4
2^1 = 2^1
The rate of reaction is first order with respect to Hbn
Let us consider the third and fourth reactions. The concentration of Hbn is held constant and that of CO was tripled.
1.5 * 10^-3/5 * 10^-4 = 1.872 * 10^-3/6.24 * 10^-4
3^1 = 3^1
The reaction is also first order with respect to CO
b) The overall order of reaction is 1 + 1=2
c) The rate equation is;
Rate = k [CO] [Hbn]
d) 3.12 * 10^-4 = k [5 * 10^-4] [1.34 * 10^-3]
k = 3.12 * 10^-4 /[5 * 10^-4] [1.34 * 10^-3]
k = 3.12 * 10^-4/6.7 * 10^-7
k = 4.7 * 10^2 mmol-1 L s-1
e) The reaction occurs in one step because;
1) The rate law agrees with the experimental data.
2) The sum of the order of reaction of each specie in the rate law gives the overall order of reaction.
