All categories

2 years ago

PLZZZ HELP ME WHAT DOES x=?????? WHOEVER ANSWERS FORST GETS BRAINLIEST THANKYOUUU

Mathematics

2 answers:

Anna [14]2 years ago

7 0

First we can label the x in 3x as x sub 1 and the angle we need to find as x sub 2

Then, set the bugle equal to each other: 3x=51

X=51/3=17

Then find x sub 2

17+x=180

X=180-17

X=163 degrees

Vinil7 [7]2 years ago

6 0

I think it’s 17 cause 51/3 is 17.

You might be interested in

Answer for brainliest!!!! YOU CAN DO IT!!!

laiz [17]

what is the question pls.

can you pls tell me

3 0

3 years ago

Read 2 more answers

5/7^3=5(7^x)<br> Find X.<br> Thanks.

Zina [86]

Hello,

$\dfrac{5}{7^3}=5*7^x\\
5*7^{-3}=5*7^x\\

\boxed{x=-3}
$

8 0

2 years ago

Can someone make sure the first 3 questions are correct and help me on the 4th one?

Ratling [72]

Sorry, I'm no help because I have no idea how to do those!

4 0

3 years ago

Convert 75 degrees to radican measure

NeX [460]

Answer:5π/12

Step-by-step explanation:

180°=π

75°=x

x=75π ➗ 180

x=5π/12

6 0

3 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago