Solution to equation
for all real values of x is
.
<u>Step-by-step explanation:</u>
Here we have ,
. Let's solve :
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⇒ 
⇒ 
By quadratic formula :
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⇒ 
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⇒ 
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But at
we have equation undefined as
. Hence only solution is :
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Since , 
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Now , General Solution is given by :
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Therefore , Solution to equation
for all real values of x is
.
In order to satisfy the requirement, this are the following that is required;First, at least one observation must be above or below 90 seconds. Second is ether the population is normally distributted or greater than (>) 30, or maybe both.
The answer in this question is A and B.
Answer:
the answers are <em>interquartile range</em> and <em>mean absolute deviation</em>
Step-by-step explanation:
Answer:
a) No. t < 0 is not part of the useful domain of the function
b) 2.0 seconds
Step-by-step explanation:
a) A graph of the function is shown below. It shows t-intercepts at t=-0.25 and t=2.0. We presume that t is measured forward from some event such as the ball being thrown or hit. The model's predicted ball location has no meaning prior to that event, when values of t are negative.
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b) It is convenient to use a graphing calculator to find the t-intercepts. Or, the equation can be solved for h=0 any of several ways algebraically. One is by factoring.
h = 0 = -16t² +28t +8 . . . . . . . . . . . . the ball hits the ground when h = 0
0 = -4(4t² -7t -2) = -4(4t +1)(t -2)
This has t-intercepts where the factors are zero, at t=-1/4 and t=2.
The ball will hit the ground after 2 seconds.
Answer:
d= -37
Step-by-step explanation:
subtract 21 on both sides which would be -16-21 and that would come to be d=-37