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3 years ago

Need help on this for brainliest

Mathematics

1 answer:

Arisa [49]3 years ago

7 0

Answer:

Your answer is letter d

Step-by-step explanation:

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3/4 x 21 show your work

Mashcka [7]

3/4 x 21 would be 15.75.
All you had to do was multiply 3/4 and 21.
Hope this helps.

4 0

3 years ago

Ron wants to buy a video game with a selling price of ?$36?, on sale for? 50% off. The sales tax in his state is 5.5 %. How much

cestrela7 [59]

Answer:

Yes, it costs $18.99.

Step-by-step explanation:

The game is originally $36 and a game 50% off is 36/2 = $18.

The sale price is $18.

The state charges 5.5% tax which means you pay 105.5% of the sale price.

1.055(18) = 18.99

The final total is 18.99 which means Ron's $19 is enough.

7 0

2 years ago

What are the coordinates of B if the midpoint of line segment AB is (2,-5) and the coordinates of point A is (4,4)?

Vlad1618 [11]

Answer:

i think it will be 20 unit diatance .

6 0

3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

2 years ago

Explain how place value could be used to find the difference between 4.23 into 2.75

Tomtit [17]

Because without place value you might put the decimal in the wrong place and that will effect the answer big time.

5 0

3 years ago