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nadya68 [22]
3 years ago
15

I need help please? :(

Mathematics
1 answer:
Tcecarenko [31]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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What statement is true? 1) 5 is a whole and not a integer. 2) 5 is a integer and not a whole. 3) 5 isn't a integer or whole 4) 5
Lorico [155]

Answer:

4

Step-by-step explanation:

5 is  an integer as well as a whole number. A whole number is one which has no fraction with it. And clearly, 5 is a positive integer. Hence, option 4 is correct that is  5 is a integer and a whole

7 0
3 years ago
(HELP ASAP) Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides.
Reika [66]
Let's say that FH and EG intersection is O,
So we have the following:
OF = 2
OH = 5

Just because F and H are midpoints it means that EO = OG = x
And as it's given the area S=35

On the other hand
S = OF*OG/2 + OG*OH/2 + OH*OE/2 + OE*OF/2 = 2*x/2 + x*5/2 + 5*x/2 + x*2/2 = 2*x + 5*x = 7*x = 35

7x = 35 so x = 35/7 = 5

Answer: 5 units

7 0
3 years ago
Read 2 more answers
Given the parent function
lozanna [386]

Answer:

Option c is right.

Step-by-step explanation:

Given is a parabola y =x^2

From that transformation is done to get parabola as

y =(0.2x)^2

We find that instead of x here we use 0.2x

i.e. New x = 5 times old x

Hence there is a horizontal expansion of scale factor 5.

We can check with any point also

When y =4, x=2 in the parent graph

But when y =4 , we have x = 10 in the new graph

i.e. there is a horizontal expansion of scale factor 5.

7 0
3 years ago
Read 2 more answers
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
Greatest common factor of 50,50
zubka84 [21]

Answer:

The greatest common factor of 50

Step-by-step explanation:

Greatest Common Factor (GCF) of two numbers

and the factors of 50 are 1, 2, 5, 10, 25 and 50.

8 0
3 years ago
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