First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3
So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3
Answer:
h = 197
Step-by-step explanation:
add 14 to each side, and h = 197
5/7 ÷ 1/3 = 5/7 × 3/1 = 15/7
Answer:
Step-by-step explanation:
