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3 years ago

Ian wanna get whooped help

Mathematics

2 answers:

tekilochka [14]3 years ago

8 0

Answer:

Step-by-step explanation:

I am not 100% sure but I hope this helps you.

Andre45 [30]3 years ago

4 0

The answer is v= A hope it helps

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Worth a lot of points answer fast and CORRECT to get the BRAINLIEST

victus00 [196]

Answer:

144 m²

Step-by-step explanation:

The net is composed of a square and 4 congruent triangles

Area o square = 6 × 6 = 36 m²

Area of 1 triangle = 0.5 × b × h = 0.5 × 6 × 9 = 3 × 9 = 27m²

Area of 4 triangles = 4 × 27 = 108 m²

Surface area = 36 + 108 = 144 m²

8 0

3 years ago

Sally, John & Mary had a discussion about Quadrilateral PQRS. Sally claimed that the figure represents an isosceles trapezoi

Kobotan [32]

Answer:

Step-by-step explanation:

Find the lenghth of the left and right sides using the distance formula to determine if the trapeziod is isosceles

$d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2}$

$PS=\sqrt{(2-1)^2+(0-4)^2}$

$PS=$ $\sqrt{17}$

$QR=\sqrt{(13-9)^{2}+(8-10)^{2}}$

$QR=$ $\sqrt{20}$

Since $PS\neq QR$ (the sides are not equal) this is not an isosceles trapezoid

Sally is incorrect and John is possibly correct.

Find the slope of the top and bottom sides to determine if this is a trapezoid.

$m=$ $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

SR: $m=$ $\frac{0-8}{2-13}$

$m=\frac{8}{11}$

PQ: $m=\frac{4-10}{1-9}$

$m=\frac{6}{8}=\frac{3}{4}$

since $mSR\neq mPQ$ (the slopes are not equal) the top and bottom sides are not parallel therefore this is not a trapezoid. Hence, John is incorrect, and Mary is ultimately correct.

5 0

3 years ago

using the numbers 5, 8, and 24, create a problem using no more than four operations (addition, subtraction, division, square, sq

irga5000 [103]

24^2 / (8+5)

576 / 13

= 44.3

7 0

3 years ago

An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6

SIZIF [17.4K]

Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6 times.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 6 trials

r = number of success = at least 4

p = probability of success which in our question is probability of

rolling a “six", i.e; p = 0.20

Let X = Number of sixes on a die

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = P(X = 4) + P(X = 5) + P(X = 6)

= $\binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}$

= $15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}$

= 0.0154 + 0.00154 + 0.000064

= 0.01696

Therefore, probability of rolling at least 4 sixes is 0.01696.

8 0

3 years ago

In which number does the 5 represent a value 10 times the value represented by the 5 in 35,187

blagie [28]

It would be 50,000 since the 5 in the other number is in the thousands place so just multiply that by 10 in place value.

3 0

3 years ago