Inner core was found to be solid after observing the motion of P waves.
Explanation:
Seismologist Inge Lehmann, studied the seismic waves of an earthquake and discovered about inner core in the mantle layer of Earth. She States that there is a boundary of discontinuity between the outer and inner core of Earth.
She studied the travel of secondary and primary waves during an earthquake and how it flows at different shells of Earth's layer which helped her in finding about the inner core of mantle. She observed that the inner core is a solid layer inside the molten layer of outer core
The requirement was established principally to address the growth of LISTERIA MONOCYTOGENES, which is a bacteria that has the capacity to continue growing even at refrigerated temperatures. The date marking procedure was put in place in order to make sure that the affected foods are discarded before the bacteria can initiate food borne illness.
Answer:
20 chromosomes
Explanation:
Mitosis is a kind of cell division that results in daughter cells with same number of chromosomes as the parent cell. It involves stages including Prophase, Metaphase, Anaphase and Telophase. In prophase, the Chromatin condenses into Chromosomes.
In Anaphase stage, the 10 chromosomes as mentioned in the question divides into opposite poles of the cell. One individual chromosome contains two sister chromatids, which actually separates in the Anaphase stage. Hence, at the end of the Anaphase stage, there will be 10 chromatids each at opposite poles of the cell. Each chromatid at this stage is considered a chromosome.
Hence, a cell with 10 chromosomes will contain 20 chromosomes (10+10 chromatids on each pole) in the Anaphase stage just before the cell divides into two in a process called CYTOKINESIS.
Answer:
c. 1:2:1
The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.
Explanation:
If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:
- RR- red
- ww - white
- Rw - pink
If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).
<u>From this cross the expected ratios are:</u>
- 1/4 RR (red)
- 2/4 Rw (pink)
- 1/4 ww (white)
So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.
<h3><u>Chi square test</u></h3>
<u>The observed frequencies were:</u>
Total 150
<u>The expected frequencies for our null hypothesis are:</u>
- 1/4 x 150 = 37.5 Red
- 2/4 x 150 = 75 Pink
- 1/4 x 150 = 37.5 white
The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.
If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991
Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.
Its dead plants and animals
