Ask question

Ask question

All categories

3 years ago

11

Please helpppp!!! im confused lol

2 answers:

arlik [135]3 years ago

8 0

Answer:

5

Step-by-step explanation:

lions [1.4K]3 years ago

6 0

Answer:

It is 4

Step-by-step explanation:

4 will always be the same it is the independent variable. The values of 5x2 and 7x are the dependent variables meaning that those values will change depending on the values of x

You might be interested in

<img src="https://tex.z-dn.net/?f=%28x%20-%207%29%28x%20-%205%29" id="TexFormula1" title="(x - 7)(x - 5)" alt="(x - 7)(x - 5)" a

Rufina [12.5K]

$\huge\textsf{Hey there!}$

$\large\textsf{(x - 7) (x - 5)}$

$\large\text{DISTRIBUTE each of the numbers}$

$\large\textsf{x(x) + (-5)x + (-7(x) + (-7)(-5)}$

$\large\textsf{x(x) = \bf x}\bf ^2$

$\large\textsf{x(-5) = \bf -5x}$

$\large\textsf{-7(x) = \bf -7x}$

$\large\textsf{(-7)(-5) = \bf 35}$

$\mathsf{x^2 - 5x -7x + 35}$

$\large\text{COMBINE the LIKE TERMS}$

$\mathsf{x^2 -(5x - 7x) + 35}$

$\mathsf{-5x -7x = \bf -12x}$

$\mathsf{x^2 - 12x + 35}$

$\boxed{\huge\text{Answer: \bf x}^2 \huge\text{\bf - 12x + 35}}\huge\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitirite1040:)}$

3 0

3 years ago

Read 2 more answers

An amount of 41,000 is borrowed for 15 years at 8.5% interest, compounded annually. If the loan is paid in full at the end of th

bazaltina [42]

Answer: $139390 must be paid back.

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = amount to be played back at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount borrowed.

From the information given,

P = 41000

r = 8.5% = 8.5/100 = 0.085

n = 1 because it was compounded once in a year.

t = 15 years

Therefore,

A = 41000(1 + 0.085/1)^1 × 15

A = 41000(1 + 0.085)^15

A = 41000(1.085)^15

A = $139390

3 0

3 years ago

Read 2 more answers

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

So

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs.

Inga [223]

-2 a b are a match. hope this helps 2-2=4

8 0

3 years ago

Part2 of the math homework

Molodets [167]

Option four is the answer bc 8^2 is 64 and so is 4^3. so for the answer to be correct, it should say = and not ≠

5 0

3 years ago