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3 years ago

12

Why is it important for the appendages of an arthropod to be joined

1 answer:

Lena [83]3 years ago

8 0

Answer:

you mean "jointed." jointed appendages give arthropods much greater movement flexibility and range.

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Which of the following describes a physical property? A) gunpowder explodes B) when two substances are mixed with a precipitate

ValentinkaMS [17]

The correct answer is C) A substance changes color when heated, but changes back when cooled. Hope this helps.

5 0

4 years ago

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Which element is most reactive and why?<br>Fe<br>Mg<br>Pb<br>Zn

murzikaleks [220]

Answer:

Magnesium is the most reactive element. it is higher than the other elements (Fe, Pb, Zn) in the electrochemical series

3 0

3 years ago

What mass of oxygen is required to completely react with 2 moles of ch4

Firlakuza [10]

The balanced reaction that describes the reaction between methane and oxygen to produce water and carbon dioxide is expressed CH4 + 2 O2 = CO2 +2H2O. Hence for 2 moles of methane used, 4 moles of oxygen are needed to react completely.

7 0

3 years ago

Which product would form if chlorine gas was bubbled through a solution of sodium bromide

Jobisdone [24]

This is what is normally termed a single replacement reaction, although don't hold me to that. It could have changed to something more modern.

$Cl_{2} + NaBr \longrightarrow Br_{2} + NaCl$

3 0

3 years ago

Read 2 more answers

A buffer solution contains 0.240 M ammonium chloride and 0.499 M ammonia. If 0.0565 moles of perchloric acid are added to 250 mL

snow_lady [41]

Answer:

The pH of the resulting solution is 9.02.

Explanation:

The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:

$pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})$

$pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.240}{0.499}) = 4.43$

$pH = 14 - pOH = 14 - 4.43 = 9.57$

Now, the perchloric acid added will react with ammonia:

$n_{NH_{3}} = 0.499moles/L*0.250 L - 0.0565 moles = 0.0683 moles$

Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:

NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O

$n_{NH_{4}Cl} = 0.240 moles/L*0.250L + 0.0565 moles = 0.1165 moles$

Finally, we can calculate the pH of the resulting solution:

$pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})$

$pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.1165 moles/0.250 L}{0.0683 moles/0.250 L}) = 4.98$

$pH = 14 - 4.98 = 9.02$

Therefore, the pH of the resulting solution is 9.02.

I hope it helps you!

5 0

3 years ago