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Gnom [1K]
3 years ago
14

9. Why do areas near large bodies of water tend to not experience large swings in temperature? (2 points)

Chemistry
2 answers:
Maslowich3 years ago
6 0
I think the correct answer from the choices listed above is the third option. Areas  near large bodies of water tend to not experience large swings in temperature because water has a high specific heat. <span>That's because water can take up lots of thermal energy, and thus preven wild swings in temperature. </span>
Serhud [2]3 years ago
4 0

Answer: Water has a high specific heat.

Explanation: Specific heat is the amount of  heat required to raise the temperature of 1 gram of substance through 1^0C.

Water has high value of specific heat as the water molecules are bonded strongly through hydrogen bonds. Thus a large amount of heat is required to break the bonds and increase the kinetic energy of molecules.

This is due to this reason that areas near large bodies of water tend to not experience large swings in temperature.

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Answer: The rate of the forward reaction increases.+The concentration of

products increases.  /The rate of the reverse reaction increases.+The concentration of products decreases.

Explanation: I got this right on Edmentum.

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3 years ago
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7 0
2 years ago
sam bought 2 1/4 pounds of swiss cheese 1 1/2 pounds of cheddar at the deli how many pounds of cheese did sam buy altogether
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8 0
3 years ago
Read 2 more answers
Seawater is around a 3% aqueous salt solution.
Eduardwww [97]

Answer:

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3 0
1 year ago
Find the formula for the hydrate<br>0.737 g MgSO3 and 0.763 g H2O
babunello [35]

The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

To know more about hydrate compound, visit the below link:

brainly.com/question/22411417

#SPJ1

6 0
1 year ago
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