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Gnom [1K]
3 years ago
14

9. Why do areas near large bodies of water tend to not experience large swings in temperature? (2 points)

Chemistry
2 answers:
Maslowich3 years ago
6 0
I think the correct answer from the choices listed above is the third option. Areas  near large bodies of water tend to not experience large swings in temperature because water has a high specific heat. <span>That's because water can take up lots of thermal energy, and thus preven wild swings in temperature. </span>
Serhud [2]3 years ago
4 0

Answer: Water has a high specific heat.

Explanation: Specific heat is the amount of  heat required to raise the temperature of 1 gram of substance through 1^0C.

Water has high value of specific heat as the water molecules are bonded strongly through hydrogen bonds. Thus a large amount of heat is required to break the bonds and increase the kinetic energy of molecules.

This is due to this reason that areas near large bodies of water tend to not experience large swings in temperature.

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Alkanes are hydrocarbons containing only single bonds. Acyclic alkanes have carbon atoms arranged in chains, whereas cycloalkane
sashaice [31]

Answer:

156 Hydrogen atoms

Explanation:

<u>Any acyclic alkane has a molecular formula that can be expressed as</u>:

CₙH₂ₙ₊₂

Where <em>n</em> is any integer and the number of carbon atoms. For example, Propane has 3 carbon atoms, this means it would have [2*3+2] 8 hydrogen atoms, resulting with a formula of C₃H₈.

An acyclic alkane with 77 carbon atoms would thus have:

2*77 + 2 = 156 hydrogen atoms

4 0
3 years ago
What best describes the collision between ideal gas molecules
Alika [10]
An ideal gas is defined as one in which all collisions between atoms or molecules are perfectly eleastic and in which there are no intermolecular attractive forces. One can visualize it as a collection of perfectly hard spheres which collide but which otherwise do not interact with each other.

Happy to help
6 0
3 years ago
If 1 kg of fuel is used in the above fusion reaction (2 1H + 3 1H--&gt; 4 2He+1 0N) , the resulting helium has a mass of 0.993 k
enot [183]
Δmc
2

For one reaction:
Mass Defect =Δm
=2(m
H
​
)−m
He
​
−m
n
​

=2(2.015)−3.017−1.009
=0.004 amu
1 amu=931.5 MeV/c
2

Hence,
E=0.004×931.5 MeV=3.724 MeV
E=3.726×1.6×10
−13
J=5.96×10
−13
J

For 1 kg of Deuterium available,
moles=
2g
1000g
​
=500
N=500N
A
​
=3.01×10
26

Energy released =
2
N
​
×5.95×10
−13
J
=8.95×10
13
6 0
3 years ago
PLZ HELP I HAVE 5 MIN!! how do waves transport energy?
nataly862011 [7]

Answer:

'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the molality of a solution formed by adding 6.30 g NH4CL to 15.7 g of water
babymother [125]

Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

Mass of NH₄Cl = 6.30 g

Mass of water = 15.7 g (15.7/1000 =0.016 kg)

Molality = ?

Solution:

Formula of molality:

Molality = Moles of solute / mass of solvent in gram

Now we will first calculate the number of moles of solute( NH₄Cl )

Number of moles = mass/ molar mass

Molar mass of  NH₄Cl = 53.491 g/mol

Number of moles = 6.30 g/  53.491 g/mol

Number of moles =  0.12 mol

Now we will calculate the molality.

Molality = Moles of solute / mass of solvent in gram

Molality =  0.12 mol / 0.016 kg

Molality = 7.5 m

or        (m=mol/kg)

Molality = 7.5 mol/kg

6 0
3 years ago
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