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Gnom [1K]
3 years ago
14

9. Why do areas near large bodies of water tend to not experience large swings in temperature? (2 points)

Chemistry
2 answers:
Maslowich3 years ago
6 0
I think the correct answer from the choices listed above is the third option. Areas  near large bodies of water tend to not experience large swings in temperature because water has a high specific heat. <span>That's because water can take up lots of thermal energy, and thus preven wild swings in temperature. </span>
Serhud [2]3 years ago
4 0

Answer: Water has a high specific heat.

Explanation: Specific heat is the amount of  heat required to raise the temperature of 1 gram of substance through 1^0C.

Water has high value of specific heat as the water molecules are bonded strongly through hydrogen bonds. Thus a large amount of heat is required to break the bonds and increase the kinetic energy of molecules.

This is due to this reason that areas near large bodies of water tend to not experience large swings in temperature.

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How many grams are in .98 mols of C6H12O6 (*round to the nearest hundredth and include the unit "g C6H12O6" after your number)
Mnenie [13.5K]
Find 1 mol
6C = 12*6 = 72
12H=1*12 = 12
O6 = 16*6 = 96
Total = 180 grams

0.98 mol
0.98 * 180 = 176.40 My answer would have to go out to 176.40

Note: anyone responding will use rounded numbers for the atomic mass. All periodic tables have variations in them. Use your periodic table to get the better atomic mass.

Answer
176.40 g C6H12O6 <<<<
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4 years ago
Identify three pairs of statements that could be used to start developing a taxonomic key for a mouse, turtle, flamingo, and cat
Zanzabum

Answer:

A dichotomous key is a tool that allows the user to determine the identity of items and organisms in the natural world. ... In each step, the user is presented with two statements based on characteristics of the organism. If the user makes the correct choice every time, the name of the organism will be revealed at the end

Explanation:

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4 years ago
Which has the most gravitational potential energy- a 10 kg ball that is 2 meters high or a 10 kg ball that is 4 meters high?
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Answer:

The 10 kg ball that is 4 meters high is greater than a 10 kg ball that is 2 meters high

Explanation:

From the question,

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P.E1 = mgh.................... Equation 1

Where P.E1 = Gravitational Potential Energy of the first ball, m = mass of the first ball, h = height of the first ball, g = acceleration due to gravity.

Given: m = 10 kg, h = 2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P.E1 = 10×2×9.8

P.E1 = 196 J.

Similarly,

Gravitational potential energy of the second ball is

P.E2 = m'gh'................... Equation 2

Where P.E2 = Gravitational potential Energy of the second ball, m' = mass of the second ball, h' = height of the second ball.

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Substitute these values into equation 2

P.E2 = 10×4×9.8

P.E2 = 392 J

From the above calculation,

P.E2 is greater than P.E1.

Hence, the 10 kg ball that is 4 meters high is greater than a 10 kg ball that is 2 meters high

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