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swat32
3 years ago
8

Choose the best statement of the octet rule from those listed below atoms lose 8 electrons to become valent atoms lose 8 electro

ns to become valent, atoms want 8 valence electrons atoms want 8 valence electrons atoms tend to react until they have 8 valence electrons atoms tend to react until they have 8 valence electrons, atoms tend to react in order to have the s2p4 configuration atoms tend to react in order to have the s2p4 configuration, atoms tend to react in order to gain 8 valence electrons atoms tend to react in order to gain 8 valence electrons
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

atoms tend to react in order to gain 8 valence electrons

Explanation:

The octet rule describes the tendency of atoms of elements to react in order to have eight electrons in their valence shell. This is because having eight valence electrons confers stability to the atoms of these elements in the compounds they form.

The octet rule only does not apply to the transition elements or the inner transition elements as only the s and p electrons are involved. the electronic configuration in atoms having an octet is s²p⁶.

For example, sodium atom has one valence electron in its valence shell but a complete octet in the inner shell; it will react with chlorine atom which has seven valence electrons to form a stable compound, sodium chloride by donating its one valence electron in order to have an octet. Similarly, the chlorine atom will then have an octet by accepting the one electron from sodium atom.

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Chlorine–35 has 17 protons. How many protons and neutrons does the isotope chlorine–36 have? 19 protons and 17 neutrons 17 proto
pochemuha

Answer:

17 protons

19 neutrons

Explanation:

Chlorine will always have the same amount of protons, and that would be 17 protons.

The atomic mass will change according to how many neutrons are present.

Cl - 35 is comprised of 17 protons and 18 neutrons.

We want to find Cl - 36:

We simply add 1 neutron. 18 + 1 = 19 neutrons.

8 0
4 years ago
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How would you distinguish benzoic acid and benzyl alcohol by their infrared spectra?
Vadim26 [7]

The OH peaks in the IR spectra of benzyl alcohol and benzoic acid should be compared and contrasted.

<h3>What is the IR spectra of Benzoic acid?</h3>
  • The right-hand portion of the infrared spectrum of benzoic acid, between wavenumbers 1500 and 400 cm-1, is referred to as the fingerprint region.
  • It results from a special combination of intricately overlapping vibrations of the atoms within the benzoic acid molecule.
<h3>What is the IR spectra of Benzyl alcohol?</h3>
  • A C-Cl bond is frequently shown by a peak at 700.
  • There are a few more peaks at 1500 that are directed at a C=C bond.
<h3>What is IR spectra?</h3>

The percent transmittance (or absorbance) of the radiation through the molecule against the radiation's wave number forms the IR spectrum.

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3 0
2 years ago
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At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
Aleks [24]

Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

We know, K_{p}=K_{c}(RT)^{\Delta n}

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and \Delta n is difference in sum of stoichiometric coefficient of products and reactants

Here \Delta n=(2)-(2+1)=-1 and T = 311 K

So, K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}

Hence value of equilibrium constant in terms of partial pressure (K_{p}) is 4.35\times 10^{-4}

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3 years ago
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Answer:

A

Explanation:

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What are the benefits and drawbacks to having a pouring temperature that is much higher than the metal’s melting temperature?
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Answer:

The main advantage would be that with the pouring temperature being much higher, there is very little chance that the metal will solidify in the mould while busy pouring. This will allow for moulds that are quite intricate to still be fully filled. The drawbacks, though, include an increased chance defects forming which relates to shrinkage (cold shots, shrinkage pores, etc). Another drawback includes entrained air being present, due to the viscosity of the metal being low because of the high pouring temperature.

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