1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fudgin [204]
3 years ago
9

What is the solute and solvent in a solution of salt water

Chemistry
1 answer:
lara [203]3 years ago
8 0

Answer:

The solute is salt and the solvent is water

Explain:

Because salt is a component the dissolves in the solvent

You might be interested in
Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
masha68 [24]

The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

For first order ln[A]=−kt+ln[A]o

45% complete, 55% remains

A = 0.55

Ao = 1

Input the value :

ln A = -kt + ln Ao

ln 0.55 = -k.65 + ln 1

-0.598=-k.65

k = 9.2 x 10⁻³ s⁻¹

The half life :

t1/2 = (ln 2) / k

t1/2 = 0.693 : 9.2 x 10⁻³

t1/2 = 75.3 s

3 0
3 years ago
What is the volume of a 28g object that has a physical property of .45g / m * L ?
sammy [17]

Answer:

12.6 grams

Explanation:

this is filler so I can send the answer and also can I get brainliness

6 0
3 years ago
I need help solving this problem !!
Tatiana [17]

Answer:

A:Boyle's Law or B:Charles's Law

 

Explanation:

5 0
4 years ago
Name CH3CH2CH2CH=CHCH3
blondinia [14]

Answer:

Hexene

hope it helps.....

8 0
3 years ago
Read 2 more answers
Other questions:
  • A solution is prepared by mixing 2.88 mol of acetone with 1.45 mol of cyclohexane at 30°C. 2nd attempt Calculate the χacetone an
    9·1 answer
  • All scientific ___________ must be based on careful and rational examinations of the facts.
    14·2 answers
  • The equation for density, d, is
    9·1 answer
  • Which of the following is the name given to a carbohydrate containing two monomers?
    9·2 answers
  • A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af
    5·1 answer
  • What influences the movement of ions and molecules?
    13·2 answers
  • A solution containing HCI would likely have
    10·2 answers
  • Aluminum oxide is formed when aluminum combines with oxygen in the air. How many grams of Al2O3 are formed when 13.6 mol of Al r
    13·1 answer
  • Which of the following would be IRRELEVANT when choosing a material to use for making overhead cables for distributing electrici
    12·1 answer
  • Draw every stereoisomer for 1,2‑difluoro‑1,2‑dimethylcyclopentane. Use wedge‑and‑dash bonds for the substituent groups, and be s
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!