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Pachacha [2.7K]
3 years ago
12

Dale made a scale drawing of a house and its lot. The scale he used was 1 inch: 7 feet. The actual length of the backyard is 35

feet. How long is the yard in the drawing?
Is it 5??????
Mathematics
1 answer:
Kipish [7]3 years ago
8 0

Answer:

5

Step-by-step explanation:

<em>35/7=5 </em>

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Which graph correctly matches the equation y = 2-x?
nalin [4]

Answer:  The answer is attached in the figure.


Step-by-step explanation:  Given are four different graphs and we are to check which one matches with the equation y = 2 - x.

We have the following points on this equation.

(0,2), (1,1), (2,0), etc.

When we try to match these points with the given graphs, the we see that these points does not match with the first, third and fourth graph. The only graph containing these points is second one.

Thus, the second option is correct. Also see the attached figure for the location of the three mentioned points.


4 0
3 years ago
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Solve the equation<br> 3x/ 8 - 4x/3 =4
Virty [35]

Answer:

x = -96/23

Step-by-step explanation

\frac{3x}{8} - \frac{4x}{3} = 4

multiply each side of equation by 24 to eliminate denominators

(24) \frac{3x}{8} - \frac{4x}{3} = 4 (24)

3(3x) - 8(4x) = 96

9x - 32x = 96

-23x = 96

x = -96/23

6 0
3 years ago
Think about converting 48% to an equivalent fraction in reduced form. If the denominator is 25, what is the numerator?
bulgar [2K]

Answer:

the numerator is 12

Step-by-step explanation:

since 48 is a percent, it would be put as 48/100 as a fraction. since both the numerator and denominator are divisible by 4, you can reduce the fraction into 12/25. Since the question is asking what the numerator was when the denominator was 25, the answer is 12.

8 0
4 years ago
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
Fred ran 4 miles in 30 minutes. Janet ran 6 miles in 40 minutes. Fred and Janet each continue running at their same rate for 1 h
borishaifa [10]
Fred: 4m: 30 minutes=8 miles per hour
janet: 6m: 40minutes= 3 miles every 20 minutes=9 miles per hour
so janet runs 1 mile more per hour

filled in:

 Fred ran 4 miles in 30 minutes. Janet ran 6 miles in 40 minutes. Fred and Janet each continue running at their same rate for 1 hour. fred will run 8 miles in 1 hour. Janet will run 9 miles in 1 hour. Janet will run 1 miles farther in 1 hour

7 0
3 years ago
Read 2 more answers
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