1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vesna_86 [32]
3 years ago
15

Help please And can you include an explanation. The question is

Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0
Step 1
Cancel terms that are in both the numerator and denominator.
36n^7p^5/9*n^4p
4n^7p^5*n^4p
Step 2
Combine exponents.
4n^7p^5n^4p
4n^11p^5p
Step 3
Combine exponents again.
4n^11p^5p
4n^11p^6
Solution
4n^11 p*^6
Nothing further can be done to this.
Hope it helped:)
You might be interested in
Jason is collecting data on the number of books students read each year. What type of data is this?
tankabanditka [31]

Answer:

b. Discrete quantitative

Step-by-step explanation:

Hope that helps

7 0
3 years ago
4 employees drive to work in the same car. the workers claim they were late to work because of a flat tire. their managers ask t
Brums [2.3K]

Answer:

The required probability is 0.015625.

Step-by-step explanation:

Consider the provided information.

There number of tires are 4.

The number of workers are 4.

The probability that individual select front drivers side tire = \frac{1}{4}

The probability that they all select front drivers side,tire is: \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}=\frac{1}{256}

Similarly,

The probability that they all select front passenger side, tire is: \frac{1}{256}

The probability that they all select rear driver side,tire is: \frac{1}{256}

The probability that they all select rear passenger side, tire is: \frac{1}{256}

Hence, the probability that all four workers select the same​ tire = \frac{1}{256}+ \frac{1}{256}+\frac{1}{256}+\frac{1}{256}

the probability that all four workers select the same​ tire = \frac{4}{256}=\frac{1}{64}=0.015625

Hence, the required probability is 0.015625.

5 0
3 years ago
A bowl contained 250 skittles. The result of 25 fruit-flavored candies pulled at random is given below. Based on this informatio
Anastaziya [24]

OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!

7 0
2 years ago
A paper cup is a perfect cylinder that is 6.4 cm tall and 3 cm across. Find the total area of paper needed to make the cup, to t
NNADVOKAT [17]

Hey there! I'm happy to help!

We want to find how much paper we need to make the cup. So, we need to find the surface area of the cylinder, which is basically the "walls and floors" of the cup. So, this is the circle on the bottom and the surrounding stuff that goes up. There is no circular top to this cup, which will be important when finding the total area of paper.

So, first we need to find how much paper we need to make the bottom circle. The formula for the area of a circle is A=πr². This r represents the radius, or the distance from the center of the circle to the edge. We are given that the cup is 3 cm completely across, and the radius is be half of that, so the radius is 1.5 cm. Let's find the area. We will use 3.14 for π.

π×1.5²=7.065

Now, we need  to find the area of the walls of the cup. The wall is a rectangle that is basically wrapped around the circle. The height of the rectangle is the height of the cup and the length of the rectangle is the circumference (perimeter) of the bottom circle because the length of the rectangle wraps completely around the circle.

First, let's find the circumference of the circle. The circumference is the diameter (distance across the circle, so 3 cm) multiplied by π. We will use 3.14 for π.

3π=9.42

So, this means that the long side of the rectangle is 9.42 cm, and now we multiply this by the height.

9.42×6.4=60.288

Now, we add the rectangle area and the bottom circle area.

60.288+7.065=67.353

But, they want us to round to the nearest centimetre, so we will just say 67 square centimetres.

An important thing to note is that this is not  the area of a normal cylinder (one with a top and a bottom circle) because it is a cup so it does not have a top. If you have a cylinder with a top and a bottom, you would just multiply the area of the circle by two, so then you have the top and bottom. If that were the case, the area of our cylinder would be 74 cm with the numbers we have been given here.

Have a wonderful day!

3 0
3 years ago
Round the whole number to the given place. 75,801,300 to the nearest million​
valina [46]

Answer:

76,000,000

Step-by-step explanation:

Look at the 100,000 place and see whether to round up or down - 8 is larger than 5, therefore 75,000,000 gets rounded up to 76,000,000

8 0
3 years ago
Other questions:
  • 12=a+5b solve for a. I think the answer is 12-5b=a but that's probably wrong
    14·1 answer
  • Consider the equation below. -2(3x-5)=16
    5·2 answers
  • The scale of a map is 1 inch equals 500 miles. City A is 650 miles from City c. How far is the distance on the map?
    6·1 answer
  • Simplify the trigonometric expression. <br> Sinx Tanx/Cosx
    5·1 answer
  • Find the measure of angle b
    15·2 answers
  • Heya! ^^
    14·2 answers
  • Through (4,-4) parallel to y=3
    12·1 answer
  • Which of the following statements describes the process for solving 4x ≥ -24?
    15·1 answer
  • A company packages their product in two sizes of cylinders. Each dimension of the larger finder
    9·1 answer
  • Can someone please answer this?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!