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2 years ago

The population of a small town in Alabama is 382 people. If the growth rate is 0.7%, what will its population be in 30 years?

1 answer:

4 0

Formula for growth:

y = initial • (percent growth + 1)^time/frequency of growth

So, since initial population is 382

Percent growth is 0.007

The time is 30 years

And it goes it by .07% every 1 year,

y = 382 • (1.007)^30/1

y= 470.9203732 people

Since we can’t have 0.9 of a person, the population after 30 years will be 470 people.

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oksian1 [2.3K]

Given:

The equation for the area of the first option is:

$x^2+200x=166400$

Where x is the side length of the current square park.

To find:

The side length of the current square park.

Solution:

We have,

$x^2+200x=166400$

It can be written as:

$x^2+200x-166400=0$

Splitting the middle term, we get

$x^2+520x-320x-166400=0$

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$(x-320)(x+520)=0$

$x=320,-520$

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

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2 years ago

What is 2/3 x 9/8 as a fraction in simplest form

tresset_1 [31]

Answer: $\frac{3}{4}$

Have attached the picture for explanation...

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2 years ago

I do not understand this. Can you please explain.

klemol [59]

Answer:

Step-by-step explanation

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2 years ago

-6 - 3(2x + 4) = 18what’s the answer

Brrunno [24]

Answer:

$x=-6$

Step-by-step explanation:

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Divide both sides by -3:

$\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}$

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Subtract 4 from both sides:

$2x+4-4=-8-4$

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3 years ago

What is the best result for h?

Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation $S=2\pi rh+2\pi r^2$ , you need to:

Apply the Subtraction property of equality and subtract $2\pi r^2$ to both sides of the equation.

Then you need to apply the Division property of equality and divide both sides of the equation by $2\pi r$ .

Then:

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2 years ago

Read 2 more answers