![\bf \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{\pi r^2 h}{3}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{volume of a cylinder}}{V=24\pi }~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{24\pi }{3}}\implies V=8\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D%5Cpi%20r%5E2%20h%7D~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cone%7D%7D%7BV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D24%5Cpi%20%7D~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cone%7D%7D%7BV%3D%5Ccfrac%7B24%5Cpi%20%7D%7B3%7D%7D%5Cimplies%20V%3D8%5Cpi)
notice the volumes, the cone's volume is really one-third that of the cylinder, assuming "h"eight and "r"adius is the same on both.
4p+5=32 or 7 packages
I got this because there are 4 bracelets in one package and she doesn't know how many packages she needs so we put p for packages next to the 4 and you already have 5 so you add the 5 to it, all of that should come out to 32. If the equation wasn't what you were looking for you subtract 5 from 32 and get 27, then you divide 4 by 27 and you get 6.75, then you round it up and you get 7. The number of packages she needs is 7.
Answer:
B
Step-by-step explanation:
table B: because when x increases y increases at the same rate and stay the same . the graph has proportional relation when it is a straight line passes through origin
for B :25/20=30/24=40/32=5/4
y=5/4 x
N/4 < -1 — we can multiply both sides with 4, so we dont have to deal with fractions.
N < -4
So, our N goes left from -4 on a number line.
-10x<-100 — divide both sides by 10
-x < -10
x > 10
X is from 10 rightwards.
5x>20 — divide both sides by 5
x > 4
X is rightwards from 4.
